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jarptica [38.1K]
3 years ago
15

Select the correct answer. On the number line, which point is closest to 3.14? 3.1 3.2 tetett HHH A B С OA. A OB B OC. C OD. D​

Mathematics
1 answer:
zimovet [89]3 years ago
3 0
The correct answer is point c.
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What is y-intercept for the line y=8x+21
Anna71 [15]

Change Y to 0.

y=8x+21

0=8x+21

-8x=21

x=\frac{21}{-8\\}

7 0
3 years ago
Solve y/2 + 22 =38 for y
KATRIN_1 [288]

Answer:

y = 32

Step-by-step explanation:

\frac{y}{2}+22=38\\\frac{y}{2}=16\\y=32

4 0
3 years ago
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Use the equation below to find y, if m=2, x=8, and b=3.<br>y=mx+b<br>y =​
fredd [130]

Answer:

19

Step-by-step explanation:

y=2×8+3

=16+3=19

please like and Mark as brainliest

6 0
3 years ago
a volley ball player servers the ball. The ball follows a path given by the equation y=-0.01x^2+0.5x+3 where x and y are measure
dolphi86 [110]

Answer:

(a)

Distance from player should be 13.82 feet or 36.2 feet

(b)

The ball will go over the net

Step-by-step explanation:

we are given

The ball follows a path given by the equation

y=-0.01x^2+0.5x+3

where

x and y are measured in feet and the origin is on the court directly below where the player hits the ball

(a)

net height is 8 ft

so, we can set y=8

and then we can solve for x

8=-0.01x^2+0.5x+3

8\cdot \:100=-0.01x^2\cdot \:100+0.5x\cdot \:100+3\cdot \:100

800=-x^2+50x+300

-x^2+50x-500=0

x^2-50x+500=0

we can use quadratic formula

x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}

x=\frac{-50\pm \sqrt{50^2-4\left(-1\right)\left(-500\right)}}{2\left(-1\right)}

x=5\left(5-\sqrt{5}\right),\:x=5\left(5+\sqrt{5}\right)

x=13.82,x=36.2

So, distance from player should be 13.82 feet or 36.2 feet

(b)

we can plug x=30 and check whether y=8 ft

y=-0.01(30)^2+0.5(30)+3

y=9ft

we know that

height of net is 8 ft

so, the ball will go over the net


5 0
3 years ago
Dr. Thomas just started an experiment. She will collect data for 6 days. How many hours is this?
Ber [7]
6 days* 24 hours per day= 144 hours

Final answer: 144 hours
4 0
3 years ago
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