Let us compute first the probability of ending up an odd number when rolling a dice. A dice has faces with numbers 1 up to 6. The odd numbers within that is 3 (1, 3 and 5). Therefore, each dice has a probability of 3/6 or 1/2. Then, you use the repeated trials formula:
Probability = n!/r!(n-r)! * p^r * q^(n-r), where n is the number of tries (n=6), r is the number tries where you get an even number (r=0), p is the probability of having an even face and q is the probability of having an odd face.
Probability = 6!/0!(6!) * (1/2)^0 * (1/2)^6
Probability = 1/64
Therefore, the probability is 1/64 or 1.56%.
Answer:
the absolute value of an integer is equation to the opposite of the integer
4/9 as a percent is (about) 44% Work:
First get a decimal by dividing 4/9(4 divided by 9) you get 0.44 repeating
Next, take away the 0. and add a percent sign at the end of 0.44. You get 44%
Truly, the answer is 44.44444...% because the four repeats, but if you round it is simply 44%
Answer: 62
Explanation: It's an equilateral triangle
It would be 7 because if you multiple 6 you get 1
