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3 years ago

Write a second inequality with the same meaning -12<= a

Mathematics

1 answer:

alexira [117]3 years ago

7 0

Answer:

a $\geq$ -12 or -48 $\leq$ 4a

Step-by-step explanation:

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3.) You deposited $5,000 in an account that pays 4% annual interest. Find the

Maurinko [17]

The balance after one year is $5200

Step-by-step explanation:

The formula to apply here is

$A=P(1+\frac{r}{n} )^{nt}$

where

A=Amount of money at the end of the period=?

P=the amount of money invested= $5000

r=rate of interest=4%=0.04

n=number of compounding per year=1

t=time in years=1

Applying the formula

$A=P(1+\frac{r}{n} )^{nt} \\\\\\A=5000(1+\frac{0.04}{1} )^{1} \\\\\\A=5000(1.04)\\\\A=5200$

A=$5200

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Compound Interest: brainly.com/question/12148233

Keywords : interest, compounded annually

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6 0

3 years ago

Car is driving at 30 kilometers per hour. How far in meters does it travel in 3 seconds?

Alenkasestr [34]

Answer:

25 meters

Step-by-step explanation:

30 km/hr = (30 km/1 hr)*(1000 m/1 km)*(1 hr/60 min)*(1 min/60 sec)

30 km/hr = (30*1000*1*1)/(1*1*60*60) meters per second

30 km/hr = 8.3333333333 m/s (approximate)

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The speed or rate is r = 8.3333333333 meters per second approximately, and the time is t = 3 seconds, so,

distance = rate*time

d = r*t

d = 8.3333333333 * 3

d = 24.9999999999

Due to rounding error, the true answer should be d = 25. We can see this if we opted to use the fraction from of 8.3333... instead of the decimal representation which isn't a perfect exact measurement.

4 0

3 years ago

The region bounded by y=x^2+1, y=x, x=-1, x=2 with square cross sections perpendicular to the x-axis.

VLD [36.1K]

Answer:

The bounded area is 5 + 5/6 square units. (or 35/6 square units)

Step-by-step explanation:

Suppose we want to find the area bounded by two functions f(x) and g(x) in a given interval (x1, x2)

Such that f(x) > g(x) in the given interval.

This area then can be calculated as the integral between x1 and x2 for f(x) - g(x).

We want to find the area bounded by:

f(x) = y = x^2 + 1

g(x) = y = x

x = -1

x = 2

To find this area, we need to f(x) - g(x) between x = -1 and x = 2

This is:

$\int\limits^2_{-1} {(f(x) - g(x))} \, dx$

$\int\limits^2_{-1} {(x^2 + 1 - x)} \, dx$

We know that:

$\int\limits^{}_{} {x} \, dx = \frac{x^2}{2}$

$\int\limits^{}_{} {1} \, dx = x$

$\int\limits^{}_{} {x^2} \, dx = \frac{x^3}{3}$

Then our integral is:

$\int\limits^2_{-1} {(x^2 + 1 - x)} \, dx = (\frac{2^3}{2} + 2 - \frac{2^2}{2}) - (\frac{(-1)^3}{3} + (-1) - \frac{(-1)^2}{2} )$

The right side is equal to:

$(4 + 2 - 2) - ( -1/3 - 1 - 1/2) = 4 + 1/3 + 1 + 1/2 = 5 + 2/6 + 3/6 = 5 + 5/6$

The bounded area is 5 + 5/6 square units.

3 0

2 years ago

Which of these strategies would eliminate a variable in the system of equations?

ahrayia [7]

Graphing or elimination

5 0

3 years ago

Find the total surface area of the rectangular prism in square millimeters.

lianna [129]

Answer:

168

Step-by-step explanation:

8 0

3 years ago