3 a + 4 k = − 6 , for a

Amira is writing a coordinate proof to show that the area of a triangle created by joining the midpoints of an isosceles triangl

Romashka [77]

Point R is the midpoint of FE¯¯¯¯¯ , so the coordinates of point R are (3a, b).

In △DEF , the length of the base, DF¯¯¯¯¯ , is
4a, and the height is 2b, so its area is
1/2×4a×2b = 4ab.

In △QRP , the length of the base, QR¯¯¯¯¯ , is
3a-a = 2a, and the height is b, so its area is 1/2×2a×b = ab .

Comparing the expressions for the areas proves that the area of the triangle created by joining the midpoints of an isosceles triangle is one-fourth the area of the larger isosceles triangle.

6 0

2 years ago

Read 2 more answers

Acute angle DOG with a measure of 45 degrees

Vlad1618 [11]

So make and angle with the measure of 45 degrees. And then label it DOG. It doesn't matter where you start labeling as long as O is your midpoint. :)

6 0

2 years ago

-4(-3x - 8) - 4x + 8 = -8x + 40

Andrew [12]

First we expand and combine the terms on the left side. This gives us

12x + 32 -4x + 8 = -8x + 40

8x + 40 = -8x + 40. Because the two sides cancel each other out when you try and bring all the x to one side, the answer is x = 0.

3 0

2 years ago

It is a six-digit

KonstantinChe [14]

Ok, the first clue is it has six digit and the second clue is it’s a whole number!
So we know it lies between 99999 and 1000000
3rd clue tells it has only 3 different digits and 4th clue tells us each are used twice!
Moving on, 5th clue says none of its digits are even! 6th speaks none are divisible be 3
So the possibilities for digits are 1, 5, 7
And it’s greater than 600000, then the 1st digit must be 7! It is divisible be 5, so last digit must be 5!
7th clue states that It’s tenth digit is same as hundred-thousand! Means the tenth digit is 7
Let’s see what we got!
{7xxx75}
Clue no 8 as you can see says that it’s thousands digit is same as unit digit
So the number now is {7x5x75}
9th clue says it’s hundreds digit is different from tens digit meaning the hundreds digit is either 1 or 7 and we used 7 two times, so it’s 1 and clue 10 says it’s ten thousands digit is 1 so the number that’s playing hide ‘n seek or most probably riddle game is 715175!

8 0

2 years ago

Greg is trying to solve a puzzle where he has to figure out two numbers, x and y. Three less than two-third of x is greater than

Fittoniya [83]

Inequation 1:

$\frac{2}{3}x-3 \geq y$

to plot the pairs (x, y) for which the inequation holds, draw the line $y=\frac{2}{3}x-3$

then pick a point in either side of the line. If that point is a solution of the inequation, than color that region of the line, if that point is not a solution, then color the other part of the line.

we do the same for the second inequation. Then the solution, is the region of the x-y axes colored in both cases.

inequation 2:

$y+ \frac{2}{3}x\ \textless \ 4$

$y\ \textless \ - \frac{2}{3} x+ 4
$

draw the lines

i) $y=\frac{2}{3}x-3$ use points (0, -3), (3, -1)

ii) $y=- \frac{2}{3} x+ 4$ use points ( 0, 4), (3, 2)

let's use the point P(3, 3) to see what region of the lines need to be coloured:

$\frac{2}{3}x-3 \geq y$ ;
$\frac{2}{3}(3)-3 \geq 3$
$2-3 \geq 3$ , not true so we color the region not containing this point

$y+ \frac{2}{3}x\ \textless \ 4$
$(3)+ \frac{2}{3}(3)\ \textless \ 4$
$3+ 5\ \textless \ 4$ not true, so we color the region not containing the point (3, 3)

The graph representing the system of inequalities is the region colored both red and blue, with the blue line not dashed, and the red line dashed.

4 0

2 years ago