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Volgvan
3 years ago
7

If m∠2 = 23° and m∠3 = 68°, what is m∠1

Mathematics
1 answer:
Harrizon [31]3 years ago
5 0

Answer:

if this is a triangle it is 89º

Step-by-step explanation:

because all the angles in a triangle add up to 180

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If 2x+z=2y and 2x+2y+z=20 what is the value of y?
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2x+z=2y\to2x=2y-z\\\\substitute\ to\ 2x+2y+z=20:\\\\(2y-z)+2y+z=20\\2y-z+2y+z=20\\4y=20\ \ \ \ /:4\\y=5\to answer
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3 years ago
A circle is inscribed in a 40º-60º-80º triangle. The points of
Vladimir [108]

Answer:

A = 50°

B = 60°

C = 70°

Step-by-step explanation:

If we draw a line from each vertex through the center of the circle, we perpendicularly bisect the line joining the adjacent tangent points.

We then know the original angle is halved and the remaining angle of each right triangle is complementary to half the original.

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3 years ago
Demand for Tablet Computers The quantity demanded per month, x, of a certain make of tablet computer is related to the average u
soldier1979 [14.2K]

x = f ( p ) = \frac { 100 } { 9 } \sqrt { 810,000 - p ^ { 2 } } } \\\\ \qquad { p ( t ) = \dfrac { 400 } { 1 + \dfrac { 1 } { 8 } \sqrt { t } } + 200 \quad ( 0 \leq t \leq 60 ) }

Answer:

12.0 tablet computers/month

Step-by-step explanation:

The average price of the tablet 25 months from now will be:

p ( 25) = \dfrac { 400 } { 1 + \dfrac { 1 } { 8 } \sqrt { 25 } } + 200 \\= \dfrac { 400 } { 1 + \dfrac { 1 } { 8 } \times 5 } + 200\\\\=\dfrac { 400 } { 1 + \dfrac { 5 } { 8 } } + 200\\p(25)=\dfrac { 5800 } {13}

Next, we determine the rate at which the quantity demanded changes with respect to time.

Using Chain Rule (and a calculator)

\dfrac{dx}{dt}= \dfrac{dx}{dp}\dfrac{dp}{dt}

\dfrac{dx}{dp}= \dfrac{d}{dp}\left[{ \dfrac { 100 } { 9 } \sqrt { 810,000 - p ^ { 2 } } }\right] =-\dfrac{100}{9}p(810,000-p^2)^{-1/2}

\dfrac{dp}{dt}=\dfrac{d}{dt}\left[\dfrac { 400 } { 1 + \dfrac { 1 } { 8 } \sqrt { t } } + 200 \right]=-25\left[1 + \dfrac { 1 } { 8 } \sqrt { t } \right]^{-2}t^{-1/2}

Therefore:

\dfrac{dx}{dt}= \left[-\dfrac{100}{9}p(810,000-p^2)^{-1/2}\right]\left[-25\left[1 + \dfrac { 1 } { 8 } \sqrt { t } \right]^{-2}t^{-1/2}\right]

Recall that at t=25, p(25)=\dfrac { 5800 } {13} \approx 446.15

Therefore:

\dfrac{dx}{dt}(25)= \left[-\dfrac{100}{9}\times 446.15(810,000-446.15^2)^{-1/2}\right]\left[-25\left[1 + \dfrac { 1 } { 8 } \sqrt {25} \right]^{-2}25^{-1/2}\right]\\=12.009

The quantity demanded per month of the tablet computers will be changing at a rate of 12 tablet computers/month correct to 1 decimal place.

8 0
3 years ago
In dales class 100 students prefer football 25 prefer baseball 50 prefer basketball which circle graph shows that data
Thepotemich [5.8K]

Answer: the first one

Step-by-step explanation:

3 0
3 years ago
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Answer: It depends on which variable you're solving for.

Step-by-step explanation:

Solving for b: b=7/8mx + -1/8xy

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                           ______

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7 0
2 years ago
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