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tino4ka555 [31]
3 years ago
9

Which is a solution to the following system of equations?

Mathematics
1 answer:
disa [49]3 years ago
3 0

Answer:

I think number B

Step-by-step explanation:

I plugged it in the calculator. And then they both were zero.

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Answer:

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MA=\sqrt{\left(\dfrac{\boxed{3}a}{2}\boxed{-}\boxed{0}\right)^2+\left(\dfrac{\boxed{b}}{2}\boxed{-}\boxed{0}\right)^2}=\\\\\\=
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NB=\sqrt{\left(\dfrac{a}{2}\boxed{-}\boxed{2}a\right)^2+\left(\dfrac{b}{2}\boxed{-}\boxed{0}\right)^2}=\\\\\\=\sqrt{\left(\dfrac{a}{2}\boxed{-}\dfrac{\boxed{4}\boxed{a}}{2}\right)^2+\left(\dfrac{b}{2}-\boxed{0}\right)^2}=\\\\\\
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Hope this helps with your mid-term too guys !

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