What is x^4 times x^2

Mathematics

1 answer:

andre [41]4 years ago

7 0

X^4 times x^2 =x^2+4=x^6

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At the beginning of year 1, Bode invests $250 at an annual simple interest rate of 3%. He makes no deposits to or withdrawals fr

Dennis_Churaev [7]

The initial investment = $250
annual simple interest rate of 3% = 0.03

Let the number of years = n
the annual increase = 0.03 * 250
At the beginning of year 1 ⇒ n = 1 ⇒⇒⇒ A(1) = 250 + 0 * 250 * 0.03 = 250

At the beginning of year 2 ⇒ n = 2 ⇒⇒⇒ A(2) = 250 + 1 * 250 * 0.03
At the beginning of year 3 ⇒ n = 3 ⇒⇒⇒ A(2) = 250 + 2 * 250 * 0.03
and so on .......
∴ The formula that can be used to find the account’s balance at the beginning of year n is:

A(n) = 250 + (n-1)(0.03 • 250)
At the beginning of year 14 ⇒ n = 14 ⇒ substitute with n at A(n)
∴ A(14) = 250 + (14-1)(0.03*250) = 347.5

So, the correct option is D.A(n) = 250 + (n – 1)(0.03 • 250); $347.50

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2/3x+6=1/2x+1/4x i need help solving this please.

olganol [36]

Hi,

Work:

$\frac{2}{3x} + 6 = \frac{1}{2} + \frac{1}{4x}$

1. Move expression 1/4x to the left side and change its sign, also move constant -6 to the right side and change its sign. Now you equation looks like this:

$\frac{2}{3x} - \frac{1}{4x} = \frac{1}{2} - 6$

2. Write all numerators above the least common denominator 12x.

$\frac{5}{12x} = \frac{1}{2} - 6$

3. Calculate the difference between 1/2 and 6.

$\frac{5}{12x} = - \frac{11}{2}$

4. Simplify equation using cross multiplication.

$10 = - 132x$

5. Switch the sides of equation.

$- 132x = 10$

6. Divide both sides of equation by -132.

$x = - \frac{5}{66}$

7. Results:

$x = - \frac{5}{66} = - 0.075$

Hope this helps.
If you have any questions about the answer comment below. Thank you!

r3t40

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