547.9 is the answer to this
Answer:
5/1 or 5
Step-by-step explanation: You find two points that the line goes on. So in this it would be 1,1 for the first one, the second one is 2,4. Then you go from the first point up or down to get to the same level at the second point. Then you go over to the left or right to meet the second point, in this graph you will go up 5 times to get to the same level. Then over 1 time to get to the point. Then you divide the rise over the run the rise is 5 and the run is 1, so you would do 5 divided by 1 and the answer of that is 5.
Hope this helps you in the future
Smiles, MysticCryptic (Aka) Jordan
Answer:
Step-by-step explanation:
-11.7
A negative and a a negative will be added together
Answer:
f ( - 2 ) = - 2
Step-by-step explanation:
Step 1:
f ( x ) = 3x + 4 Equation
Step 2:
f ( - 2 ) = 3 ( - 2 ) + 4 Input x value
Step 3:
f ( - 2 ) = - 6 + 4 Combine Like Terms
Answer:
f ( - 2 ) = - 2 Combine Like Terms
Hope This Helps :)
Let S(t) denote the amount of sugar in the tank at time t. Sugar flows in at a rate of
(0.04 kg/L) * (2 L/min) = 0.08 kg/min = 8/100 kg/min
and flows out at a rate of
(S(t)/1600 kg/L) * (2 L/min) = S(t)/800 kg/min
Then the net flow rate is governed by the differential equation
Solve for S(t):
The left side is the derivative of a product:
![\dfrac{\mathrm d}{\mathrm dt}\left[e^{t/800}S(t)\right]=\dfrac8{100}e^{t/800}](https://tex.z-dn.net/?f=%5Cdfrac%7B%5Cmathrm%20d%7D%7B%5Cmathrm%20dt%7D%5Cleft%5Be%5E%7Bt%2F800%7DS%28t%29%5Cright%5D%3D%5Cdfrac8%7B100%7De%5E%7Bt%2F800%7D)
Integrate both sides:
There's no sugar in the water at the start, so (a) S(0) = 0, which gives
and so (b) the amount of sugar in the tank at time t is
As 
, the exponential term vanishes and (c) the tank will eventually contain 64 kg of sugar.
