Answer:
The distance of the foot of the ladder to the building is 14 ft.
Step-by-step explanation:
The length of ladder = 20 ft
Angle formed by ladder with level ground, θ = 46
We are required to find out the distance of the foot of the ladder from the building
The above question can be found out by using trigonometric relations as follows;

The adjacent side of the right triangle formed by the ladder the building and the ground is the distance of the foot of the ladder from the building
The hypotenuse side is the length of the ladder = 20 ft
Therefore;
Adjacent side of triangle = Hypotenuse × cosθ
∴ Distance of the foot of the ladder from the building = Hypotenuse × cosθ
Distance of the foot of the ladder from the building = 20 ft × cos(56)
Distance of the foot of the ladder from the building = 13.893 ft
To the nearest foot, the distance of the foot of the ladder to the building = 14 ft.
Answer:
the answer is 36q^7
Step-by-step explanation:
multiply the bases and add the exponents
Answer:
A. 26.10 cm
B. 118.95 cm
Step-by-step explanation:
ST = 41^2 - 40^2 = c^2 = hypotenuse
ST = 1681 - 1600 = c^2
ST = c^2 = sq rt 681 =26.0959767014 = 26.1cm
Nearest 100th = 26.10
Length = 26.10 cm to nearest 100th
Perimeter of RSU we find (M) of SU first then add that to the other 3 lengths on the exterior of the triangle.
SU = 10^2 + 26.1^2 = c^2 = hypotenuse
SU = 100 + 681.21 = c^2
SU = c^2 = sqrt 781.21 = 27.9501341678 = 27.95cm
P TOTAL RSU = SU + TR + RS + TU
= 27.95 + 40+ 41 + 10 = 118.95cm
Answer:
4
Step-by-step explanation: