All categories

3 years ago

What is the value of x, shown below? A) 10 B) 12 C) 14 D) 60

Mathematics

2 answers:

dmitriy555 [2]3 years ago

7 0

The answer would be C) 14
since two intercepted lines always have equal opposite angles, 60= 5x-10.
so, if we input 14 as x
60=5(14)-10
60=70-10
60=60
So answer C) 14 is correct.

harina [27]3 years ago

5 0

B)12

Step-by-step explanation:

60=5x-10

+10 +10

70=5x

÷5 ÷5

x=12

Read more about transformation at:

brainly.com/question/3457976

#SPJ1

5 0

2 years ago

Write an equation in slope-intercept form of the line that passes through the point (8, 2) and is parallel to the graph of the e

Digiron [165]

Answer:

y = 4x - 30

Step-by-step explanation:

The general slope-intercept equation for a straight line is

y = mx + b

For y = 4x – 3, m = 4

=====

The other equation passes through (8,2) and has slope 4:

y = 4x +b Set x = 8, y = 2.

2 = 4×8 + b

2 = 32 + b Subtract 32 from each side

b= -30

The equation for the second graph is

y = 4x – 30

The graph below shows Equation (1) as a red line.

The graph of Equation 2 is the green line that passes through (8,2), runs parallel to Equation (1), and has a y-intercept at (0,-30.

7 0

3 years ago

Please please answer (-2)(-4)(-1)(-7)(1) = and explain

gregori [183]

Answer:

Step-by-step explanation:

(-2)(-4)(-1)(-7)(1) =

(8)(-1)(-7)(1) =

(-8)(-7)(1) =

(56)(1) = 56

hope this helps

have a good day

6 0

3 years ago

So, the question on my test was a pair of in line skates is on sale for 90. if this price represents a 9% discount from the orig

crimeas [40]

Pay attention in class

5 0

4 years ago

Find the solutions to the following linear-quadratic systems algebraically. Select the ordered pair that is one of the correct s

Ghella [55]

Answer:

(-2, 6)

Step-by-step explanation:

we have

$y=x^{2} +3x+8$ ----> equation A

$y=2x+10$ ----> equation B

equate equation A and equation B

$x^{2} +3x+8=2x+10$

$x^{2} +3x+8-2x-10=0$

$x^{2} +x-2=0$

The formula to solve a quadratic equation of the form

$ax^{2} +bx+c=0$

is equal to

$x=\frac{-b\pm\sqrt{b^{2}-4ac}} {2a}$

in this problem we have

$x^{2} +x-2=0$

$a=1\\b=1\\c=-2$

substitute in the formula

$x=\frac{-1\pm\sqrt{1^{2}-4(1)(-2)}} {2(1)}$

$x=\frac{-1\pm\sqrt{9}} {2}$

$x=\frac{-1\pm3} {2}$

$x=\frac{-1+3} {2}=1$

$x=\frac{-1-3} {2}=-2$

Find the values of y

For x=1

$y=2(1)+10=12$

For x=-2

$y=2(-2)+10=6$

therefore

The solutions are (1,12) and (-2,6)

3 0

3 years ago