Pls it’s really importa I need help !!
1 answer:
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Answer:
The answer is below
Step-by-step explanation:
The formula m = (12,000 + 12,000rt)/12t gives Keri's monthly loan payment, where r is the annual interest rate and t is the length of the loan, in years. Keri decides that she can afford, at most, a $275 monthly car payment. Give an example of an interest rate greater than 0% and a loan length that would result in a car payment Keri could afford. Provide support for your answer.
Answer: Let us assume an annual interest rate (r) = 10% = 0.1. The maximum monthly payment (m) Keri can afford is $275. i.e. m ≤ $275. Using the monthly loan payment formula, we can calculate a loan length that would result in a car payment Keri could afford.
The loan must be at least for 5.72 years for an annual interest rate (r) of 10%
<span>sin A cos B=1/2[sin(A-B)+sin(A+B)]
sin(at)*cos(2at)=1/2[sin(3at)-sin(at)]</span>
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sin(at)*cos(2at)=1/2[sin(3at)-sin(at)]</span>
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Answer:
B. The graph flips over the x-axis
Step-by-step explanation:
When you plot the coordinate pair (x, y), you plot the point 'y' units above the x-axis. If you change the sign of that (multiply the function by -1), then the point becomes (x, -y), and is plotted 'y' units below the x-axis.
The graph flips over the x-axis.
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Attached is an example of a function with its original graph (red) and the graph after being multiplied by -1 (blue). The blue graph is a reflection of the red graph across the x-axis.
