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3 years ago

Find the slope and the y-intercept of the line. y = -5/4 x + 2 slope: ?? y-intercept: ??

Mathematics

1 answer:

Kamila [148]3 years ago

3 0

Answer:

Step-by-step explanation:

Slope-intercept equation for line of slope m and y-intercept b:

y = mx+b

y = (-5/4)x + 2

slope = -5/4 = -1.25

y-intercept = 2

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Which of the combined rectangles has an area of 40 square

Galina-37 [17]

The figure A has an area of 40 squared feet.

Why?

In order to know which of the combined rectangles has an area of 40 feet squared, we need to calculate the areas each one of the figures.

So, calculating we have:

<h3>Figure A:</h3>

Two medium and equals rectangles and one big rectangle.

$SmallRectangles=(2ft*6ft)*2=12ft^{2}*2=24ft^{2}\\\\BigRectangle=(8ft-2ft-2ft)*4ft=16ft^{2}\\\\CombinedArea=24ft^{2}+16ft^{2}=40ft^{2}$

The figure A is the correct optiopn.

<h3>Figure B:</h3>

Two medium and equals rectangles and one small rectangle.

$MediumRectangles=(2ft*7ft)*2=14ft^{2}*2=28ft^{2}\\\\SmallRectangle=2ft*3ft=6ft^{2}\\\\CombinedArea=28ft^{2}+14ft^{2}=34ft^{2}$

The figure B is discarded, it's area is less than 40 squared feet.

Figure C:

One medium rectangle and one big rectangle.

$MediumRectangle=3ft*9ft=27ft^{2}\\\\BigRectangle=3ft*6ft=18ft^{2}\\\\CombinedRectangle=45ft^{2}$

The figure C is discarded, it's area is larger than 40 squared feet.

Figure D:

One medium rectangle and one big rectangle:

$SmallRectangle=3ft*8ft=24ft^{2} \\\\BigRectangle=5ft*5ft=25ft^{2}\\\\CombinedRectangle=24ft^{2}+25ft^=49ft^{2}$

The figure D is discarded, it's area is larger than 40 squared feet.

Hence, we have that the Figure A is the correct option.

Have a nice day!

5 0

3 years ago

Name two examples of quadrilaterals,

kolezko [41]

Answer:

square and rectangle

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

512, 256, 128, 64, __, __, __, ...

Cerrena [4.2K]

The complete pattern is: 512, 256, 128, 64, 32, 16, 8, ( and extended ) 4, 2, 1!

I do this pattern in my head literally all the time!

4 0

3 years ago

3/4 x 3 2/5 - 5/5(find the value of each of the following)

Triss [41]

The value of the given expression is $\frac{-13}{20}.$

Solution:

Given expression is $\frac{3}{4} \times3\frac{2}{5}-\frac{5}{5}$ .

Let us first convert mixed fraction into improper fraction.

$3\frac{2}{5}=\frac{(3\times5)+2}{5}=\frac{17}{5}$

Substitute this in the given expression.

$\frac{3}{4} \times3\frac{2}{5}-\frac{5}{5}=\frac{3}{4} \times\frac{7}{15}-\frac{5}{5}$

$=\frac{21}{60}-\frac{5}{5}$

To simplify the above expression, 21 and 60 are cancelled by 3.

$=\frac{7}{20}-\frac{1}{1}$

Do cross multiplication to make the denominator same.

$=\frac{7}{20}-\frac{20}{20}$

$=\frac{7-20}{20}$

$=\frac{-13}{20}$

The value of the given expression is $\frac{-13}{20}.$

7 0

3 years ago

Help me pls... ....

musickatia [10]

Step-by-step explanation:

1 yard = 3 feet

1 foot = 12 inches

therefore,

100 yards = 100×3×12 inches = 3600 inches

again, 1 yard = 3 feet

8 ft = 8/3 = 2.67 yards = 2 2/3 yards

1 gallon = 8 pints

1 liter = 1000 milliliters (remember, "mili" means 1/1000).

therefore,

2.2 liters = 2.2×1000 = 2200 milliliters

again, 1 liter = 1000 milliliters

therefore

1 milliliter = 1/1000 liter

670 milliliters = 670 × 1/1000 liter = 670/1000 liter =

= 0.67 liter

1 kg (kilogram) = 1000 grams ("kilo" means 1000).

we have 3 layers.

each layer weighs (cake plus icing)

1/2 kg + 100 g = 500 g + 100 g = 600 g

3 layers then weigh

3×600 g = 1800 g

the additional candle weighs 250 g.

so, the total is

1800 g + 250 g = 2050 g = 2.05 kg

area is 110 m².

1 m = 100 cm ("centi" means 1/100).

and 1 m² is then 100×100 = 10000 cm².

so, the area in cm² is

110 × 10000 = 1,100,000 cm²

the top area of one brick = 10 × 20 = 200 cm²

so, we need

1,100,000 / 200 = 11,000 / 2 = 5500 bricks

6 0

3 years ago

Find the slope and the y-intercept of the line. y = -5/4 x + 2 slope: ?? y-intercept: ??​

Find the slope and the y-intercept of the line. y = -5/4 x + 2 slope: ?? y-intercept: ??