Can u help me out ?!!

Off Topic: when you delete a place on Life360, does the other person in your circle get the notification that you have remove it

Komok [63]

I honestly don’t think so

8 0

3 years ago

Please show me How to do this number

VARVARA [1.3K]

Ok, so you have the range correct. It is 120<___<150 (It should be less than or equal to, but there's no symbol for that, to my knowledge.) But the term in the middle shouldn't be .25x The reason is because that actually quadruples the price in the end, as you seem to have found out. Rather, instead of multiplying x by .25, multiply the numbers in the range by .75. Here's why: When you reduce something in price by 25%, you are paying for 75% of the original price. Not 25%. That would be a 75% discount. So, in all actuality,your answer would be $90

6 0

3 years ago

What is the domain (in interval notation) of the following functions?

alexgriva [62]

$1.\\g(x)=\frac{3}{5x-4}\\\\D:5x-4\neq0\to5x\neq4\ \ \ /:5\to x\neq\frac{4}{5}\to x\in\mathbb{R}\ \backslash\ \{\frac{4}{5}\}\\\\2.\\h(x)=\frac{\sqrt{x}}{x-5}\\\\D:x\geq0\ \wedge\ x-5\neq0\to x\geq0\ \wedge\ x\neq5\to x\in\left$

$3.\\f(x)=\frac{\sqrt{x}}{x^2-5x}\\\\D:x\geq0\ \wedge\ x^2-5x\neq0\to x\geq0\ \wedge\ x(x-5)\neq0\\\\\to x\geq0\ \wedge\ x\neq0\ \wedge\ x\neq5\to x\in\mathbb{R^+}\ \backslash\ \{5\}\\\\4.\\g(x)=\frac{\sqrt{x}+5}{x^2-x-20}\\\\D:x\geq0\ \wedge\ x^2-x-20\neq0\to x\geq0\ \wedge\ (x+4)(x-5)\neq0\\\\\to x\geq0\ \wedge\ x\neq-4\ \wedge\ x\neq5\to x\in\left$

$5.\\h(x)=\frac{3}{x^2+1}\\\\D:x^2+1\neq0\to x^2\neq-1\to x\in\mathbb{R}\\\\6.\\f(x)=\frac{\sqrt{x-2}}{x+1}\\\\D:x-2\geq0\ \wedge\ x+1\neq0\to x\geq2\ \wedge\ x\neq-1\to x\in\left$

$7.\\g(x)=\frac{x^2}{3x^2-x-2}\\\\D:3x^2-x-2\neq0\to (3x+2)(x-1)\neq0\to x\neq-\frac{2}{3}\ \wedge\ x\neq1\\\\\to x\in\mathbb{R}\ \backslash\ \{-\frac{2}{3};\ 1\}\\\\8.\\h(x)=3(x-4)^2-7\\\\D:x\in\mathbb{R}$

4 0

3 years ago

a game where two players each throw two dice each. if any one die matches the other, you win a dollar. if there is no match, you

nadezda [96]

Yes, I would play the game, because the probability of winning is 13/18.

Probability:

Probability refer the possible occurrence of any particular event.

Given,

A game where two players each throw two dice each. if any one die matches the other, you win a dollar. if there is no match, you lose a dollar.

Here we need to find whether we able to play this one or not.

To find that one, first, we have to identify the winning scenarios,

Let us consider five winning scenarios. Lets represent the dice outcomes as A, B, C, and D, where your dice are A and B and the other player's are C and D. The five scenarios are:

1) A = B

2) A = C

3) A = D

4) B = C

5) B = D

We know that the total possible outcomes is 6^4. We can go through each scenario and count the possible outcomes. We must be careful to avoid overcounting.

Based on this,

The probability that none match is

=> 6*5*4*3/6^4

=> 360 / 1296

=> 5 / 18

So, probability of winning is,

=> 1 - 5/18

=> 13/18.

So, based on the probability the chance of winning is high. So, we can play it.

To know more about Probability here.

brainly.com/question/11234923

#SPJ4

5 0

1 year ago

Ratio equivalents to 1:2

nata0808 [166]

2:4 3:6 4:8

Any ratio equals 1:2 as long as you can divide the first number by itself to get 1 and the second number with the 1st number.
Example
2:4
Divide the first number by 2 and you get 1
Divide the second number by 2 and you get 2
So the ratio equals 1:2

Please make me brainliest

3 0

3 years ago

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