Can u help me out ?!!

if noah ran 45 minutes and john ran 6 more minutes the noah how many minutes did john run? please help

pychu [463]

Answer:51 minutes

Step-by-step explanation:

7 0

3 years ago

Select three unit rates that can be used To describe the price of juice one dollar for 12 ounces $1.59 for a pint two dollars fo

enot [183]

Answer:

$1.59 for a pint,

two dollars for a quart,

299 for a gallon

Step-by-step explanation:

Since, rate is used to compare different kinds of quantities and it is the ratio of the quantities,

Also, unit rate states the amount of first quantity corresponding to the unit amount of second quantity,

When we talk about the unit rates for a quantity,

Then it shows the price of the quantity per unit amount.

Thus, by the above explanation it is clear that,

The unit price for representing the price of juice would be,

$1.59 for a pint,

two dollars for a quart,

299 for a gallon.

Note : we do not consider 'one dollar for 12 ounces' a unit price because it is not the price per 1 ounce.

7 0

3 years ago

1/4 2/10 correct comparison answer

lubasha [3.4K]

Not exactly

2/10 = .2
1/4 = .25

1/4 is 0.05 bigger than 2/10

4 0

3 years ago

Read 2 more answers

Josslyn is thinking of a number, n and she wants her sister to guess the number. Her first clue is that seven less than six time

Snowcat [4.5K]

Answer:

1<X<=6

Step-by-step explanation:

seven less than six times her number is between negative one and twenty-nine (inclusive).

The above statement can be expressed mathematically thus;

Let the number be x

6x-7= (-1 ,29]

Hence 6x-7 = -1=>6x=6=>x=1 or

6x-7= 29=>6x=36=>x=6

Hence 1<X<=6

3 0

3 years ago

State one form of the Law of Cosines and provide a trick for writing the other two forms and explain when Law of Cosines should

Yuki888 [10]

Solving for Angles

$\displaystyle \frac{a^2 + b^2 - c^2}{2ab} = cos∠C \\ \frac{a^2 - b^2 + c^2}{2ac} = cos∠B \\ \frac{-a^2 + b^2 + c^2}{2bc} = cos∠A$

* Do not forget to use the inverse function towards the end, or elce you will throw your answer off!

Solving for Edges

$\displaystyle b^2 + a^2 - 2ba\:cos∠C = c^2 \\ c^2 + a^2 - 2ca\:cos∠B = b^2 \\ c^2 + b^2 - 2cb\:cos∠A = a^2$

You would use this law under two conditions:

One angle and two edges defined, while trying to solve for the third edge
ALL three edges defined

* Just make sure to use the inverse function towards the end, or elce you will throw your answer off!

_____________________________________________

Now, JUST IN CASE, you would use the Law of Sines under three conditions:

Two angles and one edge defined, while trying to solve for the second edge
One angle and two edges defined, while trying to solve for the second angle
ALL three angles defined [of which does not occur very often, but it all refers back to the first bullet]

* I HIGHLY suggest you keep note of all of this significant information. You will need it going into the future.

I am delighted to assist you at any time.

7 0

3 years ago