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3 years ago

Based only on the given information, it is guaranteed that AC = BC.

Mathematics

2 answers:

Alenkasestr [34]3 years ago

5 0

False :) hope it help

sweet [91]3 years ago

3 0

False hope this helps

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F(x) = 7x -9

s344n2d4d5 [400]

Answer:

Step-by-step explanation:

8 0

3 years ago

Help explain this to me: Gerome collected $9.23 more than Manuel? If Cindy still collects 2 times as much as Gerome, ho much mon

Annette [7]

$18.46
Because gerome collected $9.23 and I mult. 2 times and my answer is: $18.46

3 0

4 years ago

Raquel and her brother Marcus are huge sports fans. Combined they own 15 sports jerseys. Raquel owns double the amount of Marcus

balu736 [363]

Answer:

$x = 4$ -- Marcus

$y = 11$ -- Raquel

Step-by-step explanation:

Given

$x =Marcus$

$y = Raquel$

$x + y = 15$ -- Both

$y = 2x + 3$ -- Raquel

Required

Determine x and y

Substitute 2x + 3 for y in $x + y = 15$

$x + 2x + 3 = 15$

$3x + 3 = 15$

Collect Like Terms

$3x = 15-3$

$3x = 12$

Divide both sides by 3

$x = 4$

Substitute 4 for x in

$y = 2x + 3$

$y = 2 * 4 + 3$

$y = 8 + 3$

$y = 11$

4 0

3 years ago

Plz with steps plzzzzzz

Stella [2.4K]

Answer: $-\frac{\sqrt{2a}}{8a}$

=======================================================

Explanation:

The (x-a) in the denominator causes a problem if we tried to simply directly substitute in x = a. This is because we get a division by zero error.

The trick often used for problems like this is to rationalize the numerator as shown in the steps below.

$\displaystyle \lim_{x\to a} \frac{\sqrt{3a-x}-\sqrt{x+a}}{4(x-a)}\\\\\\\lim_{x\to a} \frac{(\sqrt{3a-x}-\sqrt{x+a})(\sqrt{3a-x}+\sqrt{x+a})}{4(x-a)(\sqrt{3a-x}+\sqrt{x+a})}\\\\\\\lim_{x\to a} \frac{(\sqrt{3a-x})^2-(\sqrt{x+a})^2}{4(x-a)(\sqrt{3a-x}+\sqrt{x+a})}\\\\\\\lim_{x\to a} \frac{3a-x-(x+a)}{4(x-a)(\sqrt{3a-x}+\sqrt{x+a})}\\\\\\\lim_{x\to a} \frac{3a-x-x-a}{4(x-a)(\sqrt{3a-x}+\sqrt{x+a})}\\\\\\$

$\displaystyle \lim_{x\to a} \frac{2a-2x}{4(x-a)(\sqrt{3a-x}+\sqrt{x+a})}\\\\\\\lim_{x\to a} \frac{-2(-a+x)}{4(x-a)(\sqrt{3a-x}+\sqrt{x+a})}\\\\\\\lim_{x\to a} \frac{-2(x-a)}{4(x-a)(\sqrt{3a-x}+\sqrt{x+a})}\\\\\\\lim_{x\to a} \frac{-2}{4(\sqrt{3a-x}+\sqrt{x+a})}\\\\\\$

At this point, the (x-a) in the denominator has been canceled out. We can now plug in x = a to see what happens

$\displaystyle L = \lim_{x\to a} \frac{-2}{4(\sqrt{3a-x}+\sqrt{x+a})}\\\\\\L = \frac{-2}{4(\sqrt{3a-a}+\sqrt{a+a})}\\\\\\L = \frac{-2}{4(\sqrt{2a}+\sqrt{2a})}\\\\\\L = \frac{-2}{4(2\sqrt{2a})}\\\\\\L = \frac{-2}{8\sqrt{2a}}\\\\\\L = \frac{-1}{4\sqrt{2a}}\\\\\\L = \frac{-1*\sqrt{2a}}{4\sqrt{2a}*\sqrt{2a}}\\\\\\L = \frac{-\sqrt{2a}}{4\sqrt{2a*2a}}\\\\\\L = \frac{-\sqrt{2a}}{4\sqrt{(2a)^2}}\\\\\\L = \frac{-\sqrt{2a}}{4*2a}\\\\\\L = -\frac{\sqrt{2a}}{8a}\\\\\\$

There's not much else to say from here since we don't know the value of 'a'. So we can stop here.

Therefore,

$\displaystyle \lim_{x\to a} \frac{\sqrt{3a-x}-\sqrt{x+a}}{4(x-a)} = -\frac{\sqrt{2a}}{8a}\\\\\\$

3 0

3 years ago

Tommy mows lawns in the summer for extra cash. He charges a flat $5 fee and then $6.50 per hour. Let h represent the number of h

Sergeu [11.5K]

Answer:

$31

Step-by-step explanation:

You have to do 6.5*4 first since 4 is the number of hours. With that, you will get 26. After that, you need to add a 5 since 5 is the flat fee. At the end, you will get $31.

7 0

3 years ago