Would you like me to help walk you through this with you figuring out the work?
Or would you prefer just an answer in math form with me explaining it along the way?
<span>h(t) = 80t – 16t^2
When you are on the ground we have zero height, h(t) = 0. This is saying that at some amount of time we will call t, the object will hit the ground. Now we solve for t to get that time
so we sub h(t) for 0.
0=80t-16t^2 move the -16t^2 to the other side
16t^2=80t divide both sides by t
16t=80 divide both sides by 16
t=5
Now... it is important to realize that there are going to be 2 answers to this equation as you have a t^2. The other answer is 0. Obviously, unless the object started on the ground, the time to hit the ground is not 0 and that answer is ruled out.
</span>
Answer:
-5/2
Step-by-step explanation:
Answer:
- 4/3 0r - 1 1/3 0r - 1.33333333 ( the 3 keeps repeating)
Step-by-step explanation:
I would suggest to use a table so....
x y
2 0
-1 4
from 0 to 4 you add 4
from 2 to -1 you subtract 3
so y/x
4/-3 = - 1 1/3 or - 1.333333
Hope this helped a little!
I'n not sure what kind of math this is but i think those two skip count. X skip counts by 1, Y skip counts by 4? If I got this wrong, please delete this.
