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3 years ago

Find the sum 6 1/4 + 7 2/3

Mathematics

2 answers:

ki77a [65]3 years ago

7 0

Answer:

13 11/12.

Step-by-step explanation:

First, we multiply 1/4 and 2/3 with it's least common denominator, 12. Now, we have 6 3/12 and 7 8/12. We now add this together to get the sum of 13 11/12.

Butoxors [25]3 years ago

4 0

13 11/12 would be the sum

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Mr. Jones eats out at his favorite buffet restaurant every Friday night. If the cost is $9 and he budgets $42 for the month, how

alexandr402 [8]

Answer:

He will be able to eat nine times.

Step-by-step explanation:

Because nine times nine is 91 which is on one less then what he has, so that means he will be able to eat there nine times. Hope I helped

7 0

3 years ago

On Tuesday Conrad had 3 times as many sales as on Monday. On Wednesday, he had 9 times as many sales as on Monday. Over the thre

Vlad1618 [11]

Answer:

Conrad had 56 sales on Monday , 168 sales on Tuesday and 504 sales on Wednesday.

Step-by-step explanation:

Let x be the no. of sales on Monday

We are given that On Tuesday Conrad had 3 times as many sales as on Monday.

So, Conrad had sales on Tuesday = 3x

We are also given that On Wednesday, he had 9 times as many sales as on Monday.

So, Conrad had sales on Wednesday = 9x

Over the three days, he had a total of 728 sales

So, x+3x+9x=728

13x=728

$x=\frac{728}{13}$

x=56

Conrad had sales on Tuesday = 3x =3(56)=168

Conrad had sales on Wednesday = 9x=9(56)=504

Hence Conrad had 56 sales on Monday , 168 sales on Tuesday and 504 sales on Wednesday.

7 0

3 years ago

How do You supposed to do this i need many method to do it.

defon

I like the substitution method. Which is when you make one equation equal only x or y and plug it into the other equation)

There is also the graphing method. If you graphed it, it might not be quite as accurate (at least on hand, on computer you would be pretty exact)

Then there is the elimination method. You multiply one of the equations by a coefficient so that you can eliminate x or y from the equation.

4 0

3 years ago

Graph the hyperbola using the transverse axis, vertices, and co-vertices:

Reptile [31]

See attachment for the graph of the hyperbola 12x^2 - 3y^2 - 108 = 0

<h3>How to graph the hyperbola?</h3>

The equation of the hyperbola is given as:

12x^2 - 3y^2 - 108 = 0

Start by calculating the transverse axis

So, we have:

<u>Transverse axis</u>

The vertices of the given hyperbola are (0, 0)

This means that

(h, k) = 0

Where

a = 3 and b = 6

The transverse axis is calculated as:

y = ±b/a(x - h) + k

So, we have:

y = ±6/3(x - 0) + 0

Evaluate the difference and sum

y = ±6/3x

Evaluate the quotient

y = ±2x

This means that the transverse axes are y = 2x and y =-2x

<u>The vertices</u>

In the above section, we have:

The vertices of the given hyperbola are (0, 0)

This means that

(h, k) = 0

<u>The co-vertices</u>

In the above section, we have:

The vertices of the given hyperbola are (0, 0)

This means that

(h, k) = 0

And

a = 3 and b = 6

The co-vertices are

(h - a, k) and (h + a, k)

So, we have:

(0 - 3, 0) and (0 + 3, 0)

Evaluate

(-3,0) and (3, 0)

See attachment for the graph of the hyperbola

Read more about hyperbola at:

brainly.com/question/26250569

#SPJ1

4 0

2 years ago

The null and alternative hypotheses are given. Determine whether the hypothesis test is left-tailed, right-tailed, or two-tail

WINSTONCH [101]

Answer: Two-tailed test.

Population mean is the parameter which is tested.

Step-by-step explanation:

Given : $H_0: \mu=105$

$H_1:\mu\neq105$

We know that , the alternative hypothesis ( $H_1$ ) indicates kind of the hypothesis test we need to perform whether left-tailed, right-tailed, or two-tailed.

Here, the alternative hypothesis ( $H_1$ ) is two-tailed, so the hypothesis test is a two-tailed test.

Also, the parameter present in the hypothesis is $\mu$ which is a symbol to represent the population mean.

Thus , Population mean is the parameter which is tested.

8 0

3 years ago