Question

Please help. Write as a single logarithm, a) log(13)+log(4) b) log(small 5)(14)-log(small 5)(2)

Answer 1

Answer:

a) $\log 52$

b) $\log_57$

Step-by-step explanation:

Use logarithm properties:

$\log_ab+\log_ac=\log_a(b\cdot c)\\ \\\log_ab-\log_ac=\log_a\dfrac{b}{c}$

Then

a) $\log 13+\log 4=\log 13\cdot 4=\log 52$

b) $\log_514-\log _52=\log _5\dfrac{14}{2}=\log _57$