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ss7ja [257]
3 years ago
15

How do you use the order of operations to solve this problem:

Mathematics
1 answer:
Delicious77 [7]3 years ago
7 0
First you do “Parenthesis”. So add to get 11. Next you do “Multiplication”. So multiply 7 and 11 to get 77. Last you do “Subtraction”. Final answer is 73.
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I need help I think it's A but IDK
denis-greek [22]
Its if u think it is :)
7 0
3 years ago
Read 2 more answers
Help!! please! Will mark Brainliest!
Karo-lina-s [1.5K]

Answer:

A) 264 ft^2, 4 gallons

Step-by-step explanation:

Area of rectangle = 12 ft x 18 ft = 216 ft^2

Area of triangle = 1/2 (28- 18)(12) = 1/2(10)(12) = 60 ft^2

Area of window: 3 ft x 4 ft = 12 ft^2

Areas will be painting = (216 + 60) - 12 = 264 ft^2

1 gallon of paint will cover 70 ft^2 so 264 ft^2 / 70 ft^2 = 3.77 gallons

So Mr. Williams will need 4 gallons of paint to cover 264 square feet of his barn

7 0
3 years ago
when 6 is subtracted from the square of a number, the result is 5 times the number. Find the negative solution.
sveta [45]

When 6 is subtracted from the square of a number, the result is 5 times the number, then the negative solution is -1

<h3><u>Solution:</u></h3>

Given that when 6 is subtracted from the square of a number, the result is 5 times the number

To find: negative solution

Let "a" be the unknown number

Let us analyse the given sentence

square of a number = a^2

6 is subtracted from the square of a number = a^2 - 6

5 times the number = 5 \times a

<em><u>So we can frame a equation as:</u></em>

6 is subtracted from the square of a number = 5 times the number

a^2 - 6 = 5 \times a\\\\a^2 -6 -5a = 0\\\\a^2 -5a -6 = 0

<em><u>Let us solve the above quadratic equation</u></em>

For a quadratic equation ax^2 + bx + c = 0 where a \neq 0

x=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a}

Here in this problem,

a^2-5 a-6=0 \text { we have } a=1 \text { and } b=-5 \text { and } c=-6

Substituting the values in above quadratic formula, we get

\begin{array}{l}{a=\frac{-(-5) \pm \sqrt{(-5)^{2}-4(1)(-6)}}{2 \times 1}} \\\\ {a=\frac{5 \pm \sqrt{25+16}}{2}=\frac{5 \pm \sqrt{49}}{2}} \\\\ {a=\frac{5 \pm 7}{2}}\end{array}

We have two solutions for "a"

\begin{array}{l}{a=\frac{5+7}{2} \text { and } a=\frac{5-7}{2}} \\\\ {a=\frac{12}{2} \text { and } a=\frac{-2}{2}}\end{array}

<h3>a = 6 or a = -1</h3>

We have asked negative solution. So a = -1

Thus the negative solution is -1

6 0
3 years ago
What addition statement does this show?
kotykmax [81]
B. -3.4 + (-5.7)= -9.1
7 0
2 years ago
My shadow in the back. Yeah no I need help. One again.
Neporo4naja [7]

1 2/5 - (-3/5)

First, we're going to convert 1 2/5 into an improper fraction.

1 2/5 = 7/5

7/5 - (-3/5)

Subtracting a negative is the same as adding, so the problem will look like:

7/5 + 3/5

The denominators are the same, so we just add the numerators.

The answer is 10/5, or 2.

7 0
3 years ago
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