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3 years ago

BMIweight 1.62 (5'4")height 46 kg (102 Ibs)

Mathematics

1 answer:

Vesnalui [34]3 years ago

6 0

Answer:

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3 years ago

Past records indicate that the probability of online retail orders that turn out to be fraudulent is 0.08. Suppose that, on a gi

Sunny_sXe [5.5K]

Answer:

The probability that there are 2 or more fraudulent online retail orders in the sample is 0.483.

Step-by-step explanation:

We can model this with a binomial random variable, with sample size n=20 and probability of success p=0.08.

The probability of k online retail orders that turn out to be fraudulent in the sample is:

$P(x=k)=\dbinom{n}{k}p^k(1-p)^{n-k}=\dbinom{20}{k}\cdot0.08^k\cdot0.92^{20-k}$

We have to calculate the probability that 2 or more online retail orders that turn out to be fraudulent. This can be calculated as:

$P(x\geq2)=1-[P(x=0)+P(x=1)]\\\\\\P(x=0)=\dbinom{20}{0}\cdot0.08^{0}\cdot0.92^{20}=1\cdot1\cdot0.189=0.189\\\\\\P(x=1)=\dbinom{20}{1}\cdot0.08^{1}\cdot0.92^{19}=20\cdot0.08\cdot0.205=0.328\\\\\\\\P(x\geq2)=1-[0.189+0.328]\\\\P(x\geq2)=1-0.517=0.483$

The probability that there are 2 or more fraudulent online retail orders in the sample is 0.483.

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Step-by-step explanation:

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3 years ago

Use the right triangle and the given information to solve the right triangle.

Leni [432]

Answer:

a= 4.993

c = 5.824

A= 59°

C = 90°

Step-by-step explanation:

b=3, B=31°

Since it's a right angle.

C = 90°

A = 180-90-31

A= 59°

For side a and c

a/sin A = b /sin B

a = sinA * b/sin B

a= sin 59 * 3/sin31

a= 4.993

a = 5

c/sin C = b/sin B

c = sin C * b/sin B

c = sin90 * 3/sin 31

c = 1* 5.824

c = 5.824

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3 years ago

Evaluate 7m+2n-8p/n m=4, n=2, and p=1.5 please help me

mamaluj [8]

Answer:

Step-by-step explanation:

7(4)+2(2)-8(1.5)/2

28+4-12/2

20/2

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4 years ago

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BMIweight 1.62 (5'4")height 46 kg (102 Ibs)​

BMIweight 1.62 (5'4")height 46 kg (102 Ibs)