I need help with all operations with integers

Help ASAP!!!!<br> Which statement about the graph of the function y=(1/3)x are true?

mafiozo [28]

Answer:

Step-by-step explanation:

1) False: The function is decreasing (because the base, 1/3, is between 0 and 1).

2) True: The function is decreasing (see #1, above)

3) False: There is no x-intercept.

4) True: If x is 0, then y = (1/3)^0 = 1.

5) False: the range consists of the set of all real numbers greater than zero.

7 0

3 years ago

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How can you use a compatible number to estimate a quotient when dividing a decimal by a whole number?

8090 [49]

Answer: just follow these simple steps!

Step-by-step explanation:

1. Estimate the quotient.

2. Perform the division. Remember to place a zero in the quotient when the divisor is larger than the dividend. ...

3. Compare your estimate with your quotient to verify that the answer makes sense.

5 0

3 years ago

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4 times a number is decreased by 9, the result is the same as when 15 is added to twice the number. find the number

igor_vitrenko [27]

Answer:

12

Step-by-step explanation:

4*x-9=2x+15

4x-9=2x+15

-2x -2x

2x-9=15

2x=24

x=12

5 0

3 years ago

A right triangle has side lengths 4 units, 5 units, and x units what is the difference between the difference values of x?

irina [24]

Use the Pythagorean theorem.

If x is a hypotenuse, then we have:

$x^2=4^2+5^2\\\\x^2=16+25\\\\x^2=41\to x=\sqrt{41}$

If x is a leg, then we have:

$x^2+4^2=5^2\\\\x^2+16=25\ \ \ \ |-16\\\\x^2=9\to x=\sqrt9\to x=3$

Answer: $\sqrt{41}-3$

6 0

3 years ago

The sphere below has a radius of 2.5 inches and an approximate volume of 65.42 cubic inches.

Stells [14]

Part a: The radius of the second sphere is 5 inches.

Part b: The volume of the second sphere is 523.33 in³

Part c; The radius of the third sphere is 1.875 inches.

Part d: The volume of the third sphere is 27.59 in³

Explanation:

Given that the radius of the sphere is 2.5 inches.

Part a: We need to determine the radius of the second sphere.

Given that the second sphere has twice the radius of the given sphere.

Radius of the second sphere = 2 × 2.5 = 5 inches

Thus, the radius of the second sphere is 5 inches.

Part b: we need to determine the volume of the second sphere.

The formula to find the volume of the sphere is given by

$V=\frac{4}{3} \pi r^3$

Substituting $\pi=3.14$ and $r=5$ , we get,

$V=\frac{4}{3} (3.14)(125)$

$V=\frac{1580}{3}$

$V=523.3333 \ in^3$

Rounding off to two decimal places, we have,

$V=523.33 \ in^3$

Thus, the volume of the second sphere is 523.33 in³

Part c: We need to determine the radius of the third sphere

Given that the third sphere has a diameter that is three-fourths of the diameter of the given sphere.

Hence, we have,

Diameter of the third sphere = $\frac{3}{4} (5)=3.75$

Radius of the third sphere = $\frac{3.75}{2} =1.875$

Thus, the radius of the third sphere is 1.875 inches

Part d: We need to determine the volume of the third sphere

The formula to find the volume of the sphere is given by

$V=\frac{4}{3} \pi r^3$

Substituting $\pi=3.14$ and $r=1.875$ , we get,

$V=\frac{4}{3} (3.14)(1.875)^3$

$V=\frac{4}{3} (3.14)(6.59)$

$V=27.5901 \ in^3$

Rounding off to two decimal places, we have,

$V=27.59 \ in^3$

Thus, the volume of the third sphere is 27.59 in³

4 0

4 years ago