1: 121, 2: 59, 3: 59
This is for the first graph because if you look at the bottom half of a circle is 180 so since one is 121 you just have to subtract 121 from 180 and you have your answer
im not sure this is right
g'(x) = 6b(-5x + 1)^5 (-5)
g'(x) = -30b(-5x +1)^5
g''(x) = -30b(5)(-5x + 1)^4 (-5)
g''(x) = 750b (-5x +1)^4
g(x) = b(−5x + 1)6 − a
when
g(-x) = b(5x +1)6 - a
g'(x) = -30b(-5x +1)^5 = 0
-5x +1 = 0
x = 15
Assuming those are the legs of the triangle and that you need to find the hypotenuse... I would use the formula: a^2+b^2=c^2
It doesn't matter what a and b are, just fill it in.
25^2+35^2=c^2
625+1225=c^2
1850=c^2
Take the square root of 1850, it isn't a perfect square so I got: 43.01.
If you want, just round it to 43, idc.
So, if I were to check my work, I would need to remember that the hypotenuse is the longest side.
Since 43 is the hypotenuse, it is the longest side.
when it tells you what R is then you show a number line with -4 less then R
The method of multiplication shown is (a) Ancient Egyptian Method
<h3>Multiplication</h3>
This involves taking the product of at least two factors which could be numbers, expressions or both
From the method shown, we can see that a factor is multiplied by multiples of 2 (i.e. doubling), till it reaches a maximum
This method is associated with the Egyptian.
Hence, the method of multiplication is (a) Ancient Egyptian Method
Read more about multiplications at:
brainly.com/question/10873737
