Question

Please help i don't have alot time ​

Answer 1

Answer:

$g\left(x\right)=-\sqrt{x+3}+8$

Step-by-step explanation:

Given function is $f\left(x\right)=-2\sqrt{x-3}+8$.

Now let's find it's range.

we know that square root function always gives positive output then:

$\sqrt{x-3}\ge0$

$-2\sqrt{x-3}\le-2\left(0\right)$

$-2\sqrt{x-3}\le0$

$-2\sqrt{x-3}+8\le0+8$

$-2\sqrt{x-3}+8\le 8$

$f(x) \le 8$

Hence range of the function is $(-\infty,8]$.

we can repeat same process to find the range of all the given choices.

we will find that only 3rd choice has same range.

Hence final answer is $g\left(x\right)=-\sqrt{x+3}+8$