Answer:
The answer to this question is given below in the explanation section.
Explanation:
Increasing ROM (Read Only Memory) in your computer does not increase efficiency or improve the performance of your system. ROM is typically used to hold programs and data that do not change very frequently (if at all) and they typically survive power loss to the system. Increasing ROM does not increase the speed of CPU performance.
However, it is noted that increasing RAM (Random Access Memory) can increase the overall efficiency of the system and it also improves the performance of CPU speed. As you add more RAM to your system, it will increase the speed of CPU as you added more RAM into the system. Adding more ROM could reduce the amount of a program that is installed on a slower disk or other external memory devices.
Answer:
Examples of input devices include keyboards, mice, scanners, digital cameras and joysticks.
Explanation:
A radiologist’s computer monitor has higher resolution than most computer screens. Resolution refers to the: <u>number of horizontal and vertical pixels on the screen.</u>
<u>Explanation:</u>
The resolution of a screen refers to the size and number of pixels that are displayed on a screen. The more pixels a screen has, the more information is displayed on it without the user having to scroll for it.
More pixels also define and enhance the clarity of the pictures and content displayed on the screen. Pixels combine in different ratios to provide different viewing experiences for users.
<span>by expanding the binary number as the sum of different powers of 2. For example:
0000 0110 #binary ==
1*2^3 + 1*2^2 = 12
</span>
Answer:
The answer is 69.3 ms
Explanation:
if 1 MiB = 0.008388608 Gb
then 3 MiB = 3 x 0.008388608 = 0.025165824 Gb.
since the bandwidth is equally shared amongst two users, each user gets equal share of the bandwidth which is Total Bandwidth/Number of Users.(
The bandwidth for each user = 30.8/2 = 15.4 Gbps.
The time taken for the message to reach from host A to host B = 0.025165824/15.4 s = 0.00163414441 which is = 1.63 ms.
The link connection requires a setup time of 67.7 ms
Therefore, the net time required is = 67.7 ms +1.63 ms = 69.3 ms.
