Describe PROM, EPROM and EEPROM memories
1 answer:
You might be interested in
Answer:
Explanation:
The following program is written in Java. Using the program code from Purchase class in 5.13 I created each one of the fruit objects. Then I set the price for each object using the setPrice method. Then I set the number of each fruit that I intended on buying with the setNumberBought method. Finally, I called each objects getTotalCost method to get the final price of each object which was all added to the totalCost instance variable. This instance variable was printed as the total cost of the bill at the end of the program. My code HIGHLIGHTED BELOW
//Entire code is in text file attached below.
//MY CODE HERE
DecimalFormat df = new DecimalFormat("0.00");
oranges.setPrice(10, 2.99);
oranges.setNumberBought(2*12);
eggs.setPrice(12, 1.69);
eggs.setNumberBought(2*12);
apples.setPrice(3, 1);
apples.setNumberBought(20);
watermelons.setPrice(1, 4.39);
watermelons.setNumberBought(2);
bagels.setPrice(6, 3.50);
bagels.setNumberBought(12);
totalCost = oranges.getTotalCost() + eggs.getTotalCost() + apples.getTotalCost() + watermelons.getTotalCost() + bagels.getTotalCost();
System.out.println("Total Cost: $" + df.format(totalCost));
}
}
Answer:
(1)Minterms complement = XYZ (2) Compliment of Minterms = Σm(0,1, 2 , 4 , 6) (3) (X+Y+Z) (4) Minimized SOP = Z + XY
Manterms = πM
Explanation:
Solution
Recall that:
Given the function F (X, Y , Z)=Σm(0,1, 2 , 4 , 6)
(1) Canonical Disjunctive Normal Form: In boolean algebra, the boolean function can be expressed as Canonical Disjunctive form known as minterms
In Minterm we assign 'I' to each uncomplimented variable and '0' to each complemented/complementary variable
For the given question stated we ave the following:
Minterms = XYZ, XYZ, XYZ, XYZ, XYZ.
(2) Canonical Conjunctive Normal Form: In boolean algebra, the boolean function can be expressed as Canonical Disjunctive form known as maxterms.
In Maxterms we assign '0' to each uncomplimented variable and '1' to each complemented/complementary variable
Compliment of Minterms = Σm(0,1, 2 , 4 , 6)
Maxterms = πM
Note: Kindly find an attached copy of the complete solution to this question below.
