Answer:
it stores the largest value in list (the maximum) in foo
Explanation:
Initially foo is assigned as the first element of the list
Inside the loop, every element in the list will be compared with foo, starting from the second element. If an element is greater than foo, the new value of the foo will be that element. At the end of the loop, foo will be equal to the largest element in the list.
Variables can be useful because they hold a certain number/data value that can easily be accessed and changed. For example, in a game, a players score is a variable that changes as the player gets more points; ie coins, items, etc.
MS-DOS is a command-line operating system.
Therefore, the best answer is Command-line.
Answer:
The correct option for this question is File.
Explanation:
Answer:
// here is code in c++ to find the approx value of "e".
#include <bits/stdc++.h>
using namespace std;
// function to find factorial of a number
double fact(int n){
double f =1.0;
// if n=0 then return 1
if(n==0)
return 1;
for(int a=1;a<=n;++a)
f = f *a;
// return the factorial of number
return f;
}
// driver function
int main()
{
// variable
int n;
double sum=0;
cout<<"enter n:";
// read the value of n
cin>>n;
// Calculate the sum of the series
for (int x = 0; x <= n; x++)
{
sum += 1.0/fact(x);
}
// print the approx value of "e"
cout<<"Approx Value of e is: "<<sum<<endl;
return 0;
}
Explanation:
Read the value of "n" from user. Declare and initialize variable "sum" to store the sum of series.Create a function to Calculate the factorial of a given number. Calculate the sum of all the term of the series 1+1/1!+1/2!.....+1/n!.This will be the approx value of "e".
Output:
enter n:12
Approx Value of e is: 2.71828
