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olga nikolaevna [1]
3 years ago
7

Describe PROM, EPROM and EEPROM memories​

Computers and Technology
1 answer:
skelet666 [1.2K]3 years ago
7 0

Answer:

Explanation:

PROM is a Read Only Memory (ROM) that can be modified only once by a user while EPROM is a programmable ROM that can be erased and reused. EEPROM, on the other hand, is a user-modifiable ROM that can be erased and reprogrammed repeatedly through a normal electrical voltage.

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The following code accomplishes which of the tasks written below? Assume list is an int array that stores positive int values on
worty [1.4K]

Answer:

it stores the largest value in list (the maximum) in foo

Explanation:

Initially foo is assigned as the first element of the list

Inside the loop, every element in the list will be compared with foo, starting from the second element. If an element is greater than foo, the new value of the foo will be that element. At the end of the loop, foo will be equal to the largest element in the list.

5 0
3 years ago
Why are variables useful in programming?
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Variables can be useful because they hold a certain number/data value that can easily be accessed and changed. For example, in a game, a players score is a variable that changes as the player gets more points; ie coins, items, etc.

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What kind of operating system is MS-DOS?
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MS-DOS is a command-line operating system.

Therefore, the best answer is Command-line.

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3 years ago
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If you cannot find a template on your computer that was appropriate for your task, what should you do?
DanielleElmas [232]

Answer:

The correct option for this question is File.

Explanation:

5 0
2 years ago
The value of the mathematical constant e can be expressed as an infinite series: e=1+1/1!+1/2!+1/3!+... Write a program that app
LUCKY_DIMON [66]

Answer:

// here is code in c++ to find the approx value of "e".

#include <bits/stdc++.h>

using namespace std;

// function to find factorial of a number

double fact(int n){

double f =1.0;

// if n=0 then return 1

if(n==0)

return 1;

for(int a=1;a<=n;++a)

       f = f *a;

// return the factorial of number

return f;

}

// driver function

int main()

{

// variable

int n;

double sum=0;

cout<<"enter n:";

// read the value of n

cin>>n;

// Calculate the sum of the series

  for (int x = 0; x <= n; x++)

  {

     sum += 1.0/fact(x);

  }

  // print the approx value of "e"

    cout<<"Approx Value of e is: "<<sum<<endl;

return 0;

}

Explanation:

Read the value of "n" from user. Declare and initialize variable "sum" to store the sum of series.Create a function to Calculate the factorial of a given number. Calculate the sum of all the term of the series 1+1/1!+1/2!.....+1/n!.This will be the approx value of "e".

Output:

enter n:12

Approx Value of e is: 2.71828

6 0
3 years ago
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