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loris [4]
3 years ago
15

Kim uses decals to decorate 5 cars and 2 motorbikes. She uses 2/3 of the decals on the cars and 2/5 of the remaining on the moto

rbikes. She has 6 decals left. How many decals does Kim use on each car?​
Mathematics
1 answer:
stiks02 [169]3 years ago
4 0

Answer:

I decal per car and motor bike

Step-by-step explanation:

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PLEASE HELP now I really need to know​
Leona [35]

Answer:

Step-by-step explanation:

-2.5 + 5n - 1.5n

-2.5 + 3.5n

Option B is the correct answer

6 0
3 years ago
Read 2 more answers
You randomly draw a marble from a bag of marbles that contains 3 blie marbles, 4 green marbles, and 5 red marbles. What is P?
Licemer1 [7]

The question is incomplete! Complete question along with answer and explanation is provided below.

Question:

You randomly draw a marble from a bag of marbles that contains 3 blue marbles, 4 green marbles, and 5 red marbles. What is P?

a) selecting a blue marble

b) selecting a green marble

c) selecting a red marble

Answer:

a) P(blue marble) = 1/4

b) P(green marble) = 1/3

c) P(red marble) = 5/12

Step-by-step explanation:

a) The probability of selecting a blue marble is given by,

P(blue marble) = no. of blue marbles/total no. of marbles

Where number of blue marbles = 3

Total number of marbles = 3 + 4 + 5 = 12

P(blue marble) = 3/12

P(blue marble) = 1/4

b) The probability of selecting a green marble is given by,

P(green marble) = no. of green marbles/total no. of marbles

Number of green marbles = 4

Total number of marbles = 12

P(green marble) = 4/12

P(green marble) = 1/3

c) The probability of selecting a red marble is given by,

P(red marble) = no. of red marbles/total no. of marbles

Where number of red marbles = 5

Total number of marbles = 12

P(red marble) = 5/12

So, the probabilities are

P(blue marble) = 1/4

P(green marble) = 1/3

P(red marble) = 5/12

6 0
3 years ago
Which ratio forms a proportion with 25/35
Art [367]
5/7 is your answer

25/5 = 5
35/5 = 35

5:7 is proportionate to 25:35

hope this helps
4 0
3 years ago
V3
valentinak56 [21]

Question:

The angle \theta_1 is located in Quadrant III, and sin(\theta_1) = - \sqrt{\frac{3}{2}}.

What is the value of cos(\theta_1) ?

Express your answer exactly. cos(\theta1) = ________

Answer:

cos(\theta_1) = - \frac{1}{2}

Step-by-step explanation:

Given:

sin(\theta_1) = - \sqrt{\frac{3}{2}}

Since the angle \theta_1 is located in Quadrant III, we have:

sin(\theta_1) = sin(\pi + \frac{\pi}{3})

\theta_1 = \pi + \frac{\pi}{3}

\theta_1 = \frac{4 \pi}{3}

Thus, cos(\theta_1) =

cos(\theta_1) = cos(\pi + \frac{\pi}{3})

cos(\theta_1) = -cos(\frac{\pi}{3})

cos(\theta_1) = - \frac{1}{2}

3 0
4 years ago
How to solve equation x/6 + 7 = 20?
hoa [83]
X/6 + 7 = 20

subtract 7 from each side

x/6 + 7 - 7 = 20 - 7
x/6 = 13

multiply each side by 6 to get x alone

x/6 • 6 = 13•6
x = 78
4 0
3 years ago
Read 2 more answers
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