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3 years ago

Determine which property is demonstrated below;

Mathematics

1 answer:

aniked [119]3 years ago

3 0

Answer:

symmetric property

Step-by-step explanation:

The <em>symmetric property</em> is the one that tells you A=B means also B=A.

The obfuscating factor in this question is the renaming of angle SZW to angle WZS. Both names refer to the same angle.

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What is 190 cups i pints

netineya [11]

There are 2 cups in every pint so you do 190/2 and that's 95 pints.

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3 years ago

3/5 of the pets in the animal shelter are dogs. There are 15 dogs at the shelter. How many animals are not dogs? HINT: Draw a ba

iren2701 [21]

3/5 of fifteen is 9 because that's the same as saying (3/5)*15 = (45/5) = 9. Since 3/5 animals are dogs, 2/5 aren't, and 15 - 9 leaves 6 animals that aren't dogs.

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3 years ago

Billy conducted an experiment by rolling a a standard number die 500 times.

artcher [175]

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3 years ago

Subtract the given function and indicate the domain of the difference

maxonik [38]

Answer:

The domain is $x\in (-\infty,\infty).$

Step-by-step explanation:

Given functions $f(x)=x^2+3x+1$ and $g(x)=2x^2-4x-1$

Subtract these two functions:

$f(x)-g(x)\\ \\=(x^2+3x+1)-(2x^2-4x-1)\\ \\=x^2+3x+1-2x^2+4x+1\\ \\=(x^2-2x^2)+(3x+4x)+(1+1)\\ \\=-x^2+7x+2$

Plot these difference on the coordinate plane (see attached diagram). This function is defined for all vlues of x, so the domain is $x\in (-\infty,\infty).$

6 0

4 years ago

From a window 20 feet above the ground, the angle of elevation to the top of a building across

Nikitich [7]

Answer: The answer is 381.85 feet.

Step-by-step explanation: Given that a window is 20 feet above the ground. From there, the angle of elevation to the top of a building across the street is 78°, and the angle of depression to the base of the same building is 15°. We are to calculate the height of the building across the street.

This situation is framed very nicely in the attached figure, where

BG = 20 feet, ∠AWB = 78°, ∠WAB = WBG = 15° and AH = height of the bulding across the street = ?

From the right-angled triangle WGB, we have

$\dfrac{WG}{WB}=\tan 15^\circ\\\\\\\Rightarrow \dfrac{20}{b}=\tan 15^\circ\\\\\\\Rightarrow b=\dfrac{20}{\tan 15^\circ},$

and from the right-angled triangle WAB, we have'

$\dfrac{AB}{WB}=\tan 78^\circ\\\\\\\Rightarrow \dfrac{h}{b}=\tan 15^\circ\\\\\\\Rightarrow h=\tan 78^\circ\times\dfrac{20}{\tan 15^\circ}\\\\\\\Rightarrow h=361.85.$

Therefore, AH = AB + BH = h + GB = 361.85+20 = 381.85 feet.

Thus, the height of the building across the street is 381.85 feet.

8 0

3 years ago