All categories

3 years ago

PLEASE BE 100% SURE the answer choices are attached

Mathematics

1 answer:

DerKrebs [107]3 years ago

4 0

B) should be your answer

The first one (the one given), is 6 "points" (forgot what it's called sorry) from 0 on all sides. To dilate it 1/3, divide 6 and 3

6/3 = 2

The one's that have points that land on points with 2 in it is B

so B is your best answer

hope this helps

You might be interested in

If angle 3 is 3x and angle 5 is 2x+30, what are the measures of angle 3 and 5?

Crank

Answer:

Step-by-step explanation:

5 0

3 years ago

600 ÷ 300 hey answers

Alika [10]

Answer:

Step-by-step explanation:

I hope this helps you :)

5 0

3 years ago

Read 2 more answers

A rectangular pan has a length that is the width. The total area of the pan is 432 in.2. What is the width of the cake pan? A =

spayn [35]

Answer:

Let width = w

length = 4w/3

Area = 432 = length*width = w*4w/3

4w^2/3 = 432

w^2 = 432*3/4 = 324

w = 18

so the width of the cake pan is 18 inches.

4 0

3 years ago

Which value would make the statement true? 2/? is greater than 4/12 ? A.4 B.6 C.12 D.24

Liula [17]

Answer:

A.4

Step-by-step explanation:

Because 4/12 is simplified to 1/3 and 2/4 would be simplified to 1/2. 1/2 > 1/4

6 0

3 years ago

I DONT KNOW THESE! HELP!

kkurt [141]

Answer:

20. x = 5, y = -2

21. x = 11, y = 12

22. x = 22, y = 11

23. x = 11, y = 10

Step-by-step explanation:

20. Opposite sides in the parallelogram are congruent, so

$2y+18=3x-1\\ \\6x-3=17-5y$

Solve this system of two equations:

$\left\{\begin{array}{l}2y-3x=-19\\ \\6x+5y=20\end{array}\right.$

Multiply the first equation by 2 and add two equations:

$2(2y-3x)+6x+5y=2\cdot (-19)+20\\ \\4y-6x+6x+5y=-38+20\\ \\9y=-18\\ \\y=-2$

Substitute it into the first equation:

$2\cdot (-2)-3x=-19\\ \\-3x=-19+4\\ \\-3x=-15\\ \\x=5$

21. Opposite angles in the parallelogram are congruent, so

$11x+5=10y+6$

Consecutive angles are supplementary, so

$6x-y+11x+5=180^{\circ}$

Solve this system of two equations:

$\left\{\begin{array}{l}11x-10y=1\\ \\17x-y=175\end{array}\right.$

From the second equation

$y=17x-175$

Substitute it into the first equation:

$11x-10(17x-175)=1\\ \\11x-170x+1750=1\\ \\-159x=-1749\\ \\x=11\\ \\y=17\cdot 11-175=187-175=12$

22. Opposite angles in the parallelogram are congruent, so

$2x-5=3y-12$

Consecutive angles are supplementary, so

$2x-5+7y+x=180^{\circ}$

Solve this system of two equations:

$\left\{\begin{array}{l}2x-3y=-7\\ \\3x+7y=185\end{array}\right.$

From the first equation

$x=-3.5+1.5y$

Substitute it into the second equation:

$3(-3.5+1.5y)+7y=185\\ \\-10.5+4.5y+7y=185\\ \\-105+45y+70y=1,850\\ \\115y=1,850+105\\ \\115y=1,955\\ \\y=17\\ \\x=-3.5+1.5\cdot 17=22$

23. Opposite sides in the parallelogram are congruent, so

$2x+9=4y-9\\ \\3x-5=2y+8$

Solve this system of two equations:

$\left\{\begin{array}{l}2x-4y=-18\\ \\3x-2y=13\end{array}\right.$

Multiply the second equation by 2 and subtract it from the first equation:

$2x-4y-2(3x-2y)=-18-2\cdot 13\\ \\2x-4y-6x+4y=-18-26\\ \\-4x=-44\\ \\x=11$

Substitute it into the first equation:

$2\cdot 11-4y=-18\\ \\-4y=-18-22\\ \\-4y=-40\\ \\y=10$

3 0

3 years ago