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Sholpan [36]
3 years ago
5

Please help me with this

Mathematics
1 answer:
den301095 [7]3 years ago
4 0

Answer:

i think the final awnser is 453

Step-by-step explanation:

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Después de 15 meses de haber prestado un capital al 5% de rédito, tengo que pagar de interés Q468.75. ¿Qué capital se ha prestad
Aleonysh [2.5K]

The capital borrowed, or the principal when the interest was Q468.75 is <u>Q7500</u>.

The principal P, amount borrowed, at a certain rate of interest R%, for  a time of T years, giving an interest of I, can be calculated using the formula:

P = (I * 100)/(R * T).

In the question, we are asked to find the capital borrowed, that is, the principal, when the user pays Q468.75 after 15 months at 5% of income.

Thus, Interest (I) = Q468.75, rate of interest (R) = 5%, and time (T) = 15 months = 15/12 years = 1.25 years.

Thus, the principal P, can be calculated by substituting the values in the formula: P = (I * 100)/(R * T).

P = (468.75*100)/(5*1.25),

or, P = 46875/6.25,

or, P = 7500.

Thus, the capital borrowed, or the principal when the interest was Q468.75 is <u>Q7500</u>.

The provided question is in Spanish. The question in English is:

"After 15 months of having borrowed capital at 5% of income, I have to pay Q468.75 in interest. What capital has been borrowed?"

Learn more about Interest at

brainly.com/question/25793394

#SPJ1

5 0
2 years ago
-9h - 15 = 93<br> What is the answer to this?
Svetlanka [38]

-9h = 93 + 15

-9h = 108

h =-12

3 0
2 years ago
Read 2 more answers
(9, 18)and<br> (3, n) .<br> Find<br> n
Maru [420]

I don't seem to comprehend what you are asking?

8 0
3 years ago
Put 45x+32=45-32 in slope interslept formthankyou.
Lilit [14]
Easy peasy pumpkineasy the answer issssssssssssssss 455555
7 0
3 years ago
What is the value of a in the equation 3a + b = 54, when b = 9?
nasty-shy [4]
In order to do this you have to substitute b with 9 and get 3a+9=54, now subtract 9 from both sides to leave a by itself and get 3a=45, now divide 3 in both sides to leave a by itself and get a=15

Hope this helps
4 0
3 years ago
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