3 years ago

Which set of ordered pairs represents y as a function of x?

Mathematics

2 answers:

NikAS [45]3 years ago

3 0

The only way it can be a function is if X is all different

So it has to be B

nordsb [41]3 years ago

3 0

Answer:

The answer is B

Step-by-step explanation:

The only way you know that it's a function of X is if it's all different.

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REALLY NEED HELP ON THESE 3 MATH QUESTIONS!!! (20 PTS)

hammer [34]

1. x² - 6x + 8
4*2 equals 8 and if you add 4 and 2 it gives you 6
-4-2= -6
=(x-4)(x-2)

3. the answer is A
if you plug in the points into the equation y=x
y= 1/2x + 4
given point: (4,6) x=4 y=6
6= 1/2(4)+4
6=6

7 0

4 years ago

State the relationship between the graphs of f(x) and g(x).

STALIN [3.7K]

Answer:

Step-by-step explanation:

Let me know if it's correct

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3 years ago

The lines 2x=ky+2 and (k+1)x=6y-3 have same gradient. Find possible values of k

faust18 [17]

Answer:

k = 3 or k = -4

(Anyone can correct me if I'm wrong)

Step-by-step explanation:

$2x=ky+2\to\ eq1\\(k+1)x=6y-3\to\ eq2\\$Change to this form: $y=mx+c\\ky=2x-2\\y=\frac{2x-2}{k}\\$gradient of eq1: $\frac{2}{k}\\6y=(k+1)x+3\\y=\frac{(k+1)x+3}{6}\\y=\frac{k+1}{6} x+\frac{3}{6}\\y= \frac{k+1}{6} x+\frac{1}{2}\\$gradient of eq1: $\frac{k+1}{6}\\$Since gradient, m, is the same for both lines,$\\\frac{2}{k}=\frac{k+1}{6}\\12=k^{2}+k\\k^{2}+k-12=0\\(k-3)(k+4)=0\\k=3 $ or $ k=-4$