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3 years ago

Hi please help will mark brainliest Charlie and Andie solve this problem in two different ways:

Mathematics

2 answers:

Dmitry_Shevchenko [17]3 years ago

5 0

Answer:

hope this helps!

Step-by-step explanation:

subtract/divide/a variable

credit: edgarandres9741

source: brainly.com/question/11711576

Karolina [17]3 years ago

3 0

Answer:

Step-by-step explanation:

since it was 26$ worth of snacks, first subtract 74 from 26

74-26= 48$ left

from this 48$, they bought tickets, therefore price for one ticket= 48/6=8$

therefore each ticket cost 8$

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What is x+9=2(x_1)^2 in the form of ax^2+bx +c=0

Naddik [55]

x + 9 = 2(x - 1)^2
x + 9 = 2(x^2 - 2x + 1)
x + 9 = 2x^2 - 4x + 2
2x^2 - 4x + 2 - x - 9 = 0
2x^2 - 5x -7 =0

7 0

3 years ago

Simplify: x2/6 ⋅ x2/4

Elden [556K]

Answer:

x ^2/ 6

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3 years ago

A marketing researcher wants to find a 96% confidence interval for the mean amount those visitors spend per person per day while

ki77a [65]

Answer:

$n=(\frac{2.054(12)}{4})^2 =37.97 \approx 38$

So then the minimum sample to ensure the condition given is n= 38

Step-by-step explanation:

Notation

$\bar X$ represent the sample mean for the sample

$\mu$ population mean (variable of interest)

$\sigma=12$ represent the population standard deviation

n represent the sample size

ME = 4 the margin of error desired

Solution to the problem

When we create a confidence interval for the mean the margin of error is given by this formula:

$ME=z_{\alpha/2}\frac{\sigma}{\sqrt{n}}$ (a)

And on this case we have that ME =4 and we are interested in order to find the value of n, if we solve n from equation (a) we got:

$n=(\frac{z_{\alpha/2} \sigma}{ME})^2$ (b)

The critical value for 96% of confidence interval now can be founded using the normal distribution. The significance is $\alpha=1-0.96 =0.04$ . And in excel we can use this formula to find it:"=-NORM.INV(0.02;0;1)", and we got $z_{\alpha/2}=2.054$ , replacing into formula (b) we got: