Question

Write the equation of the line that is perpendicular to the line 3x + y = 7 and passes through the point (6, -1).

Answer 1

Line:
3x+y=7
y=-3x+7

Slope of Perpendicular Line: 1/3x

For the perpendicular line to contain point (6,-1) the y-intercept would be (0,1), thus the equation of the line would be y=1/3x+1

y=1/3x+1