All categories

2 years ago

Write the equation of the line that is perpendicular to the line 3x + y = 7 and passes through the point (6, -1).

1 answer:

5 0

Line:
3x+y=7
y=-3x+7

Slope of Perpendicular Line: 1/3x

For the perpendicular line to contain point (6,-1) the y-intercept would be (0,1), thus the equation of the line would be y=1/3x+1

y=1/3x+1

You might be interested in

“Calculate the lengths of the 2 unlabeled sides” help me pleasee

soldier1979 [14.2K]

Answer:

It will be 6.5 for JG and 9.19 for JH

Step-by-step explanation:

Hope this Helped

5 0

2 years ago

Please help!! i dont know how to do any of this and i really need it done!!

Fiesta28 [93]

Answer:

you have to do length times width times height then divide by 2 :)

Step-by-step explanation:

6 0

2 years ago

At a bargain store, Jen bought 4 items that each cost the same amount. Carol bought 5 items that each cost the same amount, but

posledela

Jens items cost-x
carol-x+y

8 0

2 years ago

3. At a bargain store, Jamal bought 2 items that each cost the same amount. Isaiah bought 3 items that each cost the same amount

coldgirl [10]

Answer:

$6.75 and $4.50

Step-by-step explanation:

a) Jamal spent:

Isaiah spent:

3 (x - 2.25)

The equation is:

2x = 3(x - 2.25)

b) Solving the equation

2x = 3x - 6.75
3x - 2x = 6.75
x = 6.75

c) Jamal's items cost

$6.75 each

Isaiah's items cost

$6.75 - $2.25 = $4.50 each

7 0

2 years ago

Let f(x) = x^3 + 2x^2 + 3x + 1 and g(x)= 4x-5 Find f(x) x g(x)

Brums [2.3K]

$▪ ▪ ▪ ▪ ▪ ▪ ▪ ▪ ▪ ▪ ▪ ▪ ▪ { \huge \mathfrak{Answer}}▪ ▪ ▪ ▪ ▪ ▪ ▪ ▪ ▪ ▪ ▪ ▪ ▪ ▪$

Given :

$f(x) = {x}^{3} + 2 {x}^{2} + 3x + 1$

$g(x) = 4x - 5$

let's solve for f(x) × g(x) :

$( {x}^{3} + 2x {}^{2} + 3x + 1)(4x - 5)$

$4x {}^{4} - 5 {x}^{3} + 8 {x}^{3 } - 10 {x}^{2} + 12 {x}^{2} - 15x + 4x - 5$

$4 {x}^{4} + 3 {x}^{3} + 2 {x}^{2} - 11x - 5$

therefore, correct choice is : D

8 0

2 years ago