NEED THIS DONE ASAP If P(x) = -2(1 - x)2 +5, what is the value of P(-3)?

Mathematics

1 answer:

marusya05 [52]3 years ago

4 0

Answer:

P(-3) = -1

Step-by-step explanation:

So just substitute the value of x in the equation:

Value of x is (-3)

So:

P(x) = -2(1 - x)2 +5

P(-3) = -2(1-(-3)) 2 + 5

P(-3) = -2(4) 2 + 5

P(-3) = -8 + 2 + 5

P(-3) = -6 + 5

P(-3) = -1

You might be interested in

How is an equation like a balance scale!?! please make the response short and easy to understand !!

Sauron [17]

You have to equal out each side to fine the value of the variable.

hope this helped!!!
can u mark me brainliest plz?

5 0

3 years ago

(60 points)

natka813 [3]

Answer:

Step-by-step explanation:

$2.\\(a-b)^2=a^2-2ab+b^2\\\\x^2-16x=-8\\\\x^2-2(x)(8)=-8\\\\\text{We have}\ 2ab=2(x)(8).\ \text{Therefore}\ b=8.\\\\x^2-2(x)(8)=-8\qquad\text{add}\ 8^2=64\ \text{to both sides}\\\\x^2-2(x)(8)+8^2=-8+64\\\\(x-8)^2=56$

$5.\\2x^2+x-1=2\qquad\text{subtract 2 from both sides}\\\\2x^2+x-3=0\\\\2x^2+3x-2x-3=0\\\\x(2x+3)-1(2x+3)=0\\\\(2x+3)(x-1)=0\iff 2x+3=0\ \vee\ x-1=0\\\\2x+3=0\qquad\text{subtract 3 from both sides}\\2x=-3\qquad\text{divide both sides by 2}\\\boxed{x=-\dfrac{3}{2}}\\\\x-1=0\qquad\text{add 1 to both sides}\\\boxed{x=1}$

$6.\\2x^2-4x=0\qquad\text{divide both sides by 2}\\\\x^2-2x=0\\\\x(x-2)=0\iff x=0\ \vee\ x-2=0\\\\\boxed{x=0}\\\\x-2=0\qquad\text{add 2 to both sides}\\\boxed{x=2}$