The equation of this circle in standard form is equal to (x - 4)² + (y - 8)² = 5².
Based on the calculations, the equation of this circle in standard form is equal to (x - 4)² + (y - 8)² = 5²
The equation of a circle.
Mathematically, the standard form of the equation of a circle is given by;
(x - h)² + (y - k)² = r²
Where:
h and k represent the coordinates at the center.
r is the radius of a circle.
The midpoint of the given points represents the center of this circle:
h = (4 + 4)/2 = 4
k = (5.5 + 10.5)/2 = 8
Next, we would determine the radius by using the distance formula for coordinates:
r = √[(x₂ - x₁)² + (y₂ - y₁)²]
r = √[(4 - 4)² + (10.5 - 5.5)²]
r = √[0² + 5²]
r = √25
r = 5 units.
Therefore, the equation of this circle in standard form is equal to (x - 4)² + (y - 8)² = 5².
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Answer:
6
Step-by-step explanation:
(a^3 - b^3)/5
Let a =2 and b = -3
(2^3 - (-3)^3)/5
Exponents inside the parentheses
(8 - -27)/5
Subtracting a negative is like adding
(8+27)/5
Finish adding inside the parentheses
35/5
Divide
7
Answer:
I think the answer is b
Step-by-step explanation:
3cos(x)+3
x = –6
Solution:
Given expression is ![\sqrt[3]{x-2}+5=3](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7Bx-2%7D%2B5%3D3)
.
Step 1: Isolate the radical by subtracting 5 from both sides of the equation.
![\Rightarrow\sqrt[3]{x-2}+5-5=3-5](https://tex.z-dn.net/?f=%5CRightarrow%5Csqrt%5B3%5D%7Bx-2%7D%2B5-5%3D3-5)
![\Rightarrow\sqrt[3]{x-2}=-2](https://tex.z-dn.net/?f=%5CRightarrow%5Csqrt%5B3%5D%7Bx-2%7D%3D-2)
Step 2: Cube both sides of the equation to remove the cube root.
![\Rightarrow(\sqrt[3]{x-2})^3=(-2)^3](https://tex.z-dn.net/?f=%5CRightarrow%28%5Csqrt%5B3%5D%7Bx-2%7D%29%5E3%3D%28-2%29%5E3)
Cube and cube root get canceled in left side of the equation.
Step 3: To solve for x.
Add 2 on both sides of the equation.
Hence the solution is x = –6.
Step-by-step explanation:
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