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2 years ago

Enter the equation of the line in slope-intercept form. Slope is 1 3 , and (6, 3) is on the line.

Mathematics

1 answer:

Jlenok [28]2 years ago

7 0

Answer:

would it be zero because when you try to find the equation its just 0 so it would be y=3

Step-by-step explanation:

as you can see both the points are at 3. so i would say y=3

You might be interested in

The value 5 is an upper bound for the zeros of the function shown below.

Mice21 [21]

Answer:

The given statement that value 5 is an upper bound for the zeros of the function f(x) = x⁴ + x³ - 11x² - 9x + 18 will be true.

Step-by-step explanation:

Given

$f\left(x\right)\:=\:x^2\:+\:x^3\:-\:11x^2\:-\:9x\:+\:18$

We know the rational zeros theorem such as:

if $x=c$ is a zero of the function $f(x)$ ,

then $f(c) = 0$ .

As the $f\left(x\right)\:=\:x^2\:+\:x^3\:-\:11x^2\:-\:9x\:+\:18$ is a polynomial of degree $4$ , hence it can not have more than $4$ real zeros.

Let us put certain values in the function,

$f(5) = 448$ , $f(4) = 126$ , $f(3) = 0$ , $f(2) = -20$ ,

$f(1) = 0$ , $f(0) = 18$ , $f(-1) = 16$ , $f(-2) = 0$ , $f(-3) = 0$

From the above calculation results, we determined that $4$ zeros as

$x = -3, -2, 1,$ and $3$ .

Hence, we can check that

$f(x) = (x+3)(x+2)(x-1)(x-3)$

Observe that,

$for x > 3$ , $f(x)$ increases rapidly, so there will be no zeros for $x>3$ .

Therefore, the given statement that value 5 is an upper bound for the zeros of the function f(x) = x⁴ + x³ - 11x² - 9x + 18 will be true.

5 0

3 years ago

Please help me with this question please clarify what you're saying thank you

timurjin [86]

The question is asking for the circumference
The equation for circumference is C=2(Pi)r<span>

</span>to find the radius, half the diameter 4/2=2

the equation is now C=2(Pi)2<span>
simplify the equation...
C=4(Pi)
Pi is </span>3.1415926535897932384626433832795

Now multiply 3.1415926535897932384626433832795 times 4 = 12.566370614359172953850573533118
Round to nearest tenth...

12.6 mi

3 0

2 years ago

URGENT

kupik [55]

The best way to approach this problem is to look at the graph of the given function. Replace values of x from 1 to 24 to indicate the numbers of hours in a day. As seen on the graph, there is only one point where the port is at high tide. That would be at 1:00 am.

Looking at the graph, it would be safe for the boats to be in the port when the graph levels off at around 10 to 24. That's from 10 am to before 12 midnight. Then, they would have to stay away between 12 midnight to before 10 am.