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2 years ago

6

How do I solve this problem? It’s been awhile since I’ve done math

1 answer:

Helga [31]2 years ago

3 0

Answer:

y = C/h - 2

Step-by-step explanation:

Equation

C = (2 + y)*h

Solution

C = (2 + y)*h Divide by h

C/h = (2 + y)*h/h

C/h = 2 + y Subtract 2 from both sides

C/h-2 = 2-2+ y Combine

C/h - 2 = y

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3 years ago

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4 years ago

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Step-by-step explanation:

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3 years ago

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Margarita [4]

Answer:

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3 years ago

In the xy-plane, line l has a y-intercept of -13 and is perpendicular to the line with the equation y=-2/3x. If the point (10, b

AlekseyPX

Answer:

The value of $b$ is 2.

Step-by-step explanation:

The standard form of the equation of the line is of the form:

$y = m\cdot x + k$

Where:

$x$ , $y$ - Independent and dependent variable, dimensionless.

$m$ - Slope, dimensionless.

$k$ - y-intercept, dimensionless.

Given that line $l$ is perpendicular to $y = -\frac{2}{3}\cdot y$ , the slope is equal to:

$m = -\frac{1}{m_{\perp}}$

Where $m_{\perp}$ is the slope of the perpendicular line, dimensionless.

If $m_{\perp} = -\frac{2}{3}$ , then:

$m = -\frac{1}{\left(-\frac{2}{3}\right) }$

$m = \frac{3}{2}$

If $x = 0$ and $y = -13$ , the y-intercept of the line $l$ is:

$-13 = \frac{3}{2}\cdot (0) +k$

$k = -13$

The equation of the line $l$ is $y = \frac{3}{2}\cdot x -13$ . Given that $y = b$ and $x = 10$ , the value of $b$ is:

$b = \frac{3}{2}\cdot (10)-13$

$b = 15-13$

$b = 2$

The value of $b$ is 2.

5 0

3 years ago