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deff fn [24]
3 years ago
5

In the past, the mean running time for a certain type of flashlight battery has been 9.7 hours. The manufacturer has introduced

a change in the production method and wants to perform a hypothesis test to determine whether the mean running time has increased as a result. The hypotheses are: H 0: μ = 9.7 hours H a: μ > 9.7 hours where μ is the mean running time of the new batteries . Explain the meaning of a Type I error.
Mathematics
1 answer:
Nadya [2.5K]3 years ago
6 0

Answer:

Step-by-step explanation:

From the information given:

\mathbf{H_o: \mu = 9.7 \ hours}

\mathbf{H_1: \mu > 9.7 \ hours}

The type 1 error is rejecting \mathbf{H_o} when

The meaning of Type 1 error is rejecting the claim that the mean running time is 9.7 hours when actually the mean running time is greater than 9. 7 hour.

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hammer [34]

the answer is B

because 54x 3= 162 x3 = 486x3= 1458x3=4,374x3=13,122x3=39,366x3=118,098x3=354,294

7 0
3 years ago
Identify the relationship then solve for x
kupik [55]

These are alternate interior angles.

you would set them equal to eachother and solve for x.

10x=9x+7

subtract 9x from 10x.

x=7

the answers are bolded.

I hope this helps

5 0
3 years ago
If f'(x) = 12x^3 - 2x^2 - 17 and f(1) = 8 , find f(x).
Cloud [144]

Answer:

f(x) =  3x⁴ - \frac{2X^{3} }{3} - 17x +  \frac{68}{3}

Step-by-step explanation:

To find f'(x), we will follow the steps below:

We will start by integrating both-side of the equation

∫f'(x) = ∫(12x^3 - 2x^2 - 17)dx

f(x)  = 3x⁴ - \frac{2X^{3} }{3} - 17x + C

Then we go ahead and find C

f(1) = 8

so we will replace x by 1 in the above equation and solve for c

f(1)  = 3(1)⁴ - \frac{2(1)^{3} }{3} - 17(1) + C

8 = 3 - \frac{2}{3} - 17 + C

C =8 - 3 + 17 + \frac{2}{3}

C = 22 +  \frac{2}{3}

C =\frac{66 + 2}{3}

C = \frac{68}{3}

f(x) =  3x⁴ - \frac{2X^{3} }{3} - 17x +  \frac{68}{3}

7 0
3 years ago
Circle C with center at (−4, 6) and radius 2 is similar to circle D with center at (6, −2) and radius 4. Below is an incorrect i
BlackZzzverrR [31]

We are told that circle C has center (-4, 6) and a radius of 2.

We are told that circle D has center (6, -2) and a radius of 4.


If we move circle C's center ten units to the right and eight units down, the new center would be at (-4 + 10), (6 - 8) = (6, -2). So step 1 in the informal proof checks out - the centers are the same (which is the definition of concentric) and the shifts are right.

Let's look at our circles. Circle C has a radius of 2 and is inside circle D, whose radius is 4. Between Circle C and Circle D, the radii have a 1:2 ratio, as seen below:

\frac{1}{2} = \frac{radius--circle C}{radius--circle D}

If we dilate circle C by a factor of 2, it means we are expanding it and doubling it. Our circle has that 1:2 ratio, and doubling both sides gives us 2:4. The second step checks out.

Translated objects (or those that you shift) can be congruent, and dilated objects are used with similarity (where you stretch and squeeze). The third step checks out.


Thus, the argument is correct and the last choice is best.

3 0
3 years ago
T: 3(t + 3) + 5(3 + 2t) – 76 = 0
Setler [38]

Answer:

\huge\boxed{\sf t = 4}

Step-by-step explanation:

\sf 3(t+3)+5(3+2t)-76 = 0\\\\Expanding \ Parenthesis\\\\3t + 9 + 15 + 10t -76 = 0\\\\13t + 24 -76 = 0\\\\13t - 52 = 0\\\\Add \ 52 \ to \ both \ sides\\\\13t = 52\\\\Dividing\ both\ sides\ by\ 13\\\\t = 52/13\\\\t = 4\\\\\rule[225]{225}{2}

Hope this helped!

<h3>~AH1807</h3>
6 0
3 years ago
Read 2 more answers
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