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3 years ago

To solve the system given below using substitution, it is best to start by

Mathematics

1 answer:

Contact [7]3 years ago

8 0

Answer:

is Water is stored in response to changing demand a cause or effect....

Step-by-step explanation:

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Explain how the expanded notation method is used to multiply 82 times 3

Dovator [93]

82+82+82 is the awnser you'll be needing : )

7 0

3 years ago

Read 2 more answers

What is the value of -3(7+5)/3^2 +9(3)

Paraphin [41]

Answer:

-3(7+5)÷3*2+9(3)

-21-15÷6+27

-36÷33

-12/11

7 0

2 years ago

Pls help need asap in 10 mins stressing out ://

eimsori [14]

Answer: The correct option is

(D) {3, 10, 17, 24, …}.

Reasoning:

We are given to select the sequence that represents the following function with a domain of natural numbers :

The set of natural numbers is {1, 2, 3, 4, . . .}

to find the sequence, we need to substitute x = 1, 2, 3, 4, . . . in equation (i).

From equation (i), we get

Therefore, the sequence that represents the given function is {3, 10, 17, 24, …}.

Thus, option (D) is CORRECT.

4 0

2 years ago

I really don't get this....

rewona [7]

Seeing you don't have a graphing calculator, use the web, there are many websites dedicated to different calculators

5 0

2 years ago

Given the circle with the equation (x + 1)2 + y2 = 36, determine the location of each point with respect to the graph of the cir

kati45 [8]

$\bf \textit{equation of a circle}\\\\ 
(x- h)^2+(y- k)^2= r^2
\qquad 
center~~(\stackrel{}{ h},\stackrel{}{ k})\qquad \qquad 
radius=\stackrel{}{ r}\\\\
-------------------------------\\\\
(x+1)^2+y^2=36\implies [x-(\stackrel{h}{-1})]^2+[y-\stackrel{k}{0}]^2=\stackrel{r}{6^2}~~~~
\begin{cases}
\stackrel{center}{(-1,0)}\\
\stackrel{radius}{6}
\end{cases}$

so, that's the equation of the circle, and that's its center, any point "ON" the circle, namely on its circumference, will have a distance to the center of 6 units, since that's the radius.

$\bf ~~~~~~~~~~~~\textit{distance between 2 points}
\\\\
(\stackrel{x_1}{-1}~,~\stackrel{y_1}{0})\qquad 
A(\stackrel{x_2}{-1}~,~\stackrel{y_2}{1})\qquad \qquad 
% distance value
d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2}
\\\\\\
\stackrel{distance}{d}=\sqrt{[-1-(-1)]^2+(1-0)^2}\implies d=\sqrt{(-1+1)^2+1^2}
\\\\\\
d=\sqrt{0+1}\implies d=1$

well, the distance from the center to A is 1, namely is "inside the circle".

$\bf ~~~~~~~~~~~~\textit{distance between 2 points}
\\\\
(\stackrel{x_1}{-1}~,~\stackrel{y_1}{0})\qquad 
B(\stackrel{x_2}{-1}~,~\stackrel{y_2}{6})\\\\\\
\stackrel{distance}{d}=\sqrt{[-1-(-1)]^2+(6-0)^2}\implies d=\sqrt{(-1+1)^2+6^2}
\\\\\\
d=\sqrt{0+36}\implies d=6$

notice, the distance to B is exactly 6, and you know what that means.

$\bf ~~~~~~~~~~~~\textit{distance between 2 points}
\\\\
(\stackrel{x_1}{-1}~,~\stackrel{y_1}{0})\qquad 
C(\stackrel{x_2}{4}~,~\stackrel{y_2}{-8})
\\\\\\
\stackrel{distance}{d}=\sqrt{[4-(-1)]^2+[-8-0]^2}\implies d=\sqrt{(4+1)^2+(-8)^2}
\\\\\\
d=\sqrt{25+64}\implies d=\sqrt{89}\implies d\approx 9.43398$

notice, C is farther than the radius 6, meaning is outside the circle, hiking about on the plane.

3 0

3 years ago

Read 2 more answers