This question is easier than it seems. If there are 9 consecutive integers with the mean being 16, then 16 must be the median. So just add four on top and four below 16 to give you your range of 9 values, 12-20. 12+13+14+15+16+17+18+19+20=144, 144/9=16. So the mean of the first four numbers is (12+13+14+15)/4= 13.5. If you check, 13.5 is also the median of these four numbers.
9/5
the distance is 9 over, and 5 up.
Answer:x=2
Step-by-step explanation:
change () to x
x + -8= -6
-6+8=2
x=2
Answer:
(a) center: (0, 0); radius: 4
(b) center: (8, -3); radius: 10
(c) center: (-2, -7); radius: 7
(d) center: (6, 0); radius: 1
(e) center: (0, 0); radius: 5
(f) center: (3, 8); radius: 8
Step-by-step explanation:
In the figure attached, the complete question is shown.
Equation of a circle with center (h, k) and radius r:
(x - h)² + (y - k)² = r²
Answer:
<h2>
A(-2, 2) and B(6, 10)</h2>
Step-by-step explanation:
Given the equation of a line y = x + 4 and equation of a circle as
( x − 3 )² + ( y − 5 )² = 34, if the line and the circle intersect at points A and B, to get this points, we will substitute the equation of the line into that of the circle as shown;
We will have to expand the equation of the circle first before making the substitute.
( x − 3 )² + ( y − 5 )² = 34
x²-6x+9+y²-10y+25 = 34
x²+y²-6x+-10y+34-34 = 0
x²+y²-6x+-10y = 0
Substituting y = x+ 4 into the resulting expression;
x²+(x+4)²-6x+-10y = 0
x²+x²+8x+16-6x+-10(x+4) = 0
x²+x²+8x+16-6x+-10x-40 = 0
2x²-8x-24 = 0
x²-4x-12 = 0
(x²-6x)+(2x-12) = 0
x(x-6)+2(x-6) = 0
x+2 = 0 and x-6 = 0
x = -2 and 6
when x = -2;
y = -2+4
y = 2
when x = 6
y = 6+4
y = 10
The coordinates of the point of intersection are A(-2, 2) and B(6, 10).
