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pashok25 [27]
3 years ago
15

Pls help you can just give me the answers not the step by step

Mathematics
1 answer:
Lynna [10]3 years ago
6 0

Answer:

1: 3     2: -2     3: 12   4: 9  5:  4   6:-0.628    7:-10    8:-7  9: 2/3    10:17 11: -4

12: 11  13:30  14:7 15:-18  16:10 17:0 18:7 19:-3.6  20:6

Hope this helps

-mercury

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Y = 3/5х + 2 on a graph
Andrei [34K]

Answer:

Go to desmos graphing calculator and put your equation in and it will graph it for you I used it for my math questions like this

Step-by-step explanation:

HOPE THAT HELPS YOU

7 0
2 years ago
If n is a positive integer, how many 5-tuples of integers from 1 through n can be formed in which the elements of the 5-tuple ar
Oksana_A [137]

Answer:

n + 4 {n \choose 2} + 6 {n \choose 3} + 4 {n \choose 4} + {n \choose 5}

Step-by-step explanation:

Lets divide it in cases, then sum everything

Case (1): All 5 numbers are different

 In this case, the problem is reduced to count the number of subsets of cardinality 5 from a set of cardinality n. The order doesnt matter because once we have two different sets, we can order them descendently, and we obtain two different 5-tuples in decreasing order.

The total cardinality of this case therefore is the Combinatorial number of n with 5, in other words, the total amount of possibilities to pick 5 elements from a set of n.

{n \choose 5 } = \frac{n!}{5!(n-5)!}

Case (2): 4 numbers are different

We start this case similarly to the previous one, we count how many subsets of 4 elements we can form from a set of n elements. The answer is the combinatorial number of n with 4 {n \choose 4} .

We still have to localize the other element, that forcibly, is one of the four chosen. Therefore, the total amount of possibilities for this case is multiplied by those 4 options.

The total cardinality of this case is 4 * {n \choose 4} .

Case (3): 3 numbers are different

As we did before, we pick 3 elements from a set of n. The amount of possibilities is {n \choose 3} .

Then, we need to define the other 2 numbers. They can be the same number, in which case we have 3 possibilities, or they can be 2 different ones, in which case we have {3 \choose 2 } = 3  possibilities. Therefore, we have a total of 6 possibilities to define the other 2 numbers. That multiplies by 6 the total of cases for this part, giving a total of 6 * {n \choose 3}

Case (4): 2 numbers are different

We pick 2 numbers from a set of n, with a total of {n \choose 2}  possibilities. We have 4 options to define the other 3 numbers, they can all three of them be equal to the biggest number, there can be 2 equal to the biggest number and 1 to the smallest one, there can be 1 equal to the biggest number and 2 to the smallest one, and they can all three of them be equal to the smallest number.

The total amount of possibilities for this case is

4 * {n \choose 2}

Case (5): All numbers are the same

This is easy, he have as many possibilities as numbers the set has. In other words, n

Conclussion

By summing over all 5 cases, the total amount of possibilities to form 5-tuples of integers from 1 through n is

n + 4 {n \choose 2} + 6 {n \choose 3} + 4 {n \choose 4} + {n \choose 5}

I hope that works for you!

4 0
3 years ago
Ben had knee surgery and was given a prescription with instructions to take 4 tablets twice a day for pain on day 1, then take 3
azamat

Answer:40

Step-by-step explanation:4 tablets twice a day is 8 (4*2=8). 3 tablets twice a day (3*2=6) for days 2-6 which is 5 days (6*5=30) is 30. The 7th day is 1 tablet twice a day (1*2=2). You’re multiplying the tablets Ben has to take times 2. Add them all together and you have 40.

7 0
3 years ago
What’s the lowest common multiple of 120 and 75
andreyandreev [35.5K]
<h2>Answer:  600</h2>

Step-by-step explanation:

prime factorization of 75:

75 = 3 × 5 × 5

prime factorization of 120:

120 = 2 × 2 × 2 × 3 × 5

LCM = 2 × 2 × 2 × 3 × 5 × 5

There for the LCM = 600

* HOPEFULLY THIS HELPS:) Mark me the brainliest:)!!

5 0
3 years ago
What is the definition of the Angle Addition Postulate?
nasty-shy [4]
The angle addition postulates states that if an angle UVW has a point S lying in its interior, then the sum of angle UVS and angle SVW must equal angle UVW, or ?UVS + ?SVW= ?UVW.
8 0
3 years ago
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