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pashok25 [27]
3 years ago
15

Pls help you can just give me the answers not the step by step

Mathematics
1 answer:
Lynna [10]3 years ago
6 0

Answer:

1: 3     2: -2     3: 12   4: 9  5:  4   6:-0.628    7:-10    8:-7  9: 2/3    10:17 11: -4

12: 11  13:30  14:7 15:-18  16:10 17:0 18:7 19:-3.6  20:6

Hope this helps

-mercury

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The manufacturer of an electronic device claims that the probability of the device failing during the warranty period is 0.005.
Zielflug [23.3K]

Answer:

The  value is  P(X \ge  15) =  0.5

Step-by-step explanation:

From the question we are told that

    The probability of the device failing during the warranty period is p =  0.005

    The  sample size is  n = 3000

     The random variable  considered is  x  =  15

Generally this is distribution is binomial given the fact that there is only two out comes hence

      X  which is a variable representing a randomly selected selected electronic follows a binomial distribution i.e

     X  \~ \  B(n , p)

Now the mean is mathematically evaluated as

      \mu  =  n *  p

=>   \mu  = 3000 *  0.005

=>    \mu  =15

The standard deviation is mathematically represented as

      \sigma  =  \sqrt{np(1 -p )}

=>  \sigma  =  \sqrt{3000 *  0.005 * (1 - 0.005 )}

=>   \sigma  =  3.86

Now given that n is very large, then it mean that we can successfully apply normal approximation on this  binomial distribution

So

    P(X \ge  15) =  P( \frac{X - \mu}{\sigma }  \ge \frac{x - \mu}{\sigma } )

Now  applying  Continuity Correction we have

   P(X \ge  (15-0.5)) =  P( \frac{X - \mu}{\sigma }  > \frac{(15 -0.5) - 15}{3.86 } )

Generally  \frac{X - \mu}{\sigma }   =  Z (The \ standardized \ value  \ of  \ X)

    P(X \ge  (15-0.5)) =  P(Z >-0.130 )

From the z-table  

       P(Z >-0.130 )  =0.5

Thus  

    P(X \ge  15) =  0.5

 

   

7 0
4 years ago
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alisha [4.7K]
There are 22 roses in the vase 
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3 years ago
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Lina20 [59]

Answer:

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Step-by-step explanation:

To change degrees to radians, multiply by pi/180

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romanna [79]
You use the formula given and it usually involves dividing
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Answer:

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