Question

1/(x+4)(x-2)(x-5) excluded values

Answer 1

Answer:

see explanation

Step-by-step explanation:

The excluded values are any values of x that make the function undefined

Given

$\frac{1}{(x+4)(x-2)(x-5)}$

The denominator of the rational function cannot be zero as this would make it undefined. Equating the denominator to zero and solving gives the values that x cannot be.

(x + 4)(x - 2)(x - 5) = 0

Equate each factor to zero and solve for x

x + 4 = 0 ⇒ x = - 4

x - 2 = 0 ⇒ x = 2

x - 5 = 0 ⇒ x = 5

x = - 4, x = 2, x = 5 are the excluded values