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3 years ago

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Let A and B be 2 Ã 2 matrices. A) Does det(A + B) = det(A) + det(B)? B) Does det(AB) = det(A) det(B)? (C) Does det(AB) = det(BA)

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1 answer:

USPshnik [31]3 years ago

8 0

Answer:

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Step-by-step explanation:

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Describe the sequence of transformations from quadrilateral ABCD to A'B'C'D A: -8,8 B: 8,-2 C: 4,-8 D: 4,-2 A': 2,-10 B': 8,-10

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Answers:

See below

Step-by-step explanation:

First transformation

Reflection about the line y = 6.

This inter-converted Points A and C and Points B and D.

The coordinate transformations were (Fig. 1):

A: (-8, 8) ⟶ (-8, 4)

B: (-2, 8) ⟶ (-2, 4)

C: (-8, 4) ⟶ (-8, 8)

D: (-2, 4) ⟶ (-2, 8)

Second transformation

Translation 10 units to the right and 14 units down.

The coordinate transformations were (Fig. 2):

A: (-8, 4) ⟶ (2, -10)

B: (-2, 4) ⟶ (8, -10)

C: (-8, 8) ⟶ (2, -6)

D: (-2, 8) ⟶ (8, -6)

The transformations were:

Reflection about the line y = 6
Translation 10 units to the right and 14 units down

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The length of a rectangle is 4 cm more than twice the width. The area is 48 cm^. What is the length of the rectangle

REY [17]

Answer:

The regular length of the rectangle is 10

Step-by-step explanation:

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3 years ago

Which equation is parallel to the line y=-4x + 3?

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Any equation that has the same slope is parallel. So just find the equation with a -4x

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List the 6 congruency statements given triangle KNC is congruent to triangle GJ A. angle K is congruent to angle C; angle N is c

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The answer to your question is C

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3 years ago

A manufacturer of chocolate chips would like to know whether its bag filling machine works correctly at the 439.0 gram setting.

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<h2>Answer with explanation:</h2>

Let $\mu$ be the average weight of chocolate chips in each bag.

As per given , we have

$H_0: \mu =439.0\\\\ H_a: \mu$

Since $H_a$ is left-tailed , so we perform a left-tailed test.

Also, the population standard deviation is known $\sigm=21.0$ .

So we use z-test.

Test statistic : $z=\dfrac{\overline{x}-\mu}{\dfrac{\sigma}{\sqt{n}}}$

Substitute given value , $\overline{x}=433.0\ , n=47,\ \sigma=21 \ , \mu=439$

$z=\dfrac{433-439}{\dfrac{21}{\sqrt{47}}}\approx-1.96$

Significance level = 0.05

Decision rule : Reject $H_0$ when p-value < 0.05.

By z-table , P- value for left-tailed test = P(z<-1.96)= 1- P(z<1.96)

[∵ P(Z<-z)=1-P(Z<z)]

= 1- 0.9750

=0.025

Since , P-value(0.025) < 0.05 , so we reject the null hypothesis.

We support the claim that the machine is underfilling the bags at 0.05 significance level .

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