Since there isn't a picture of the graphs, I attached one, of my graph, to this answer.
I'm also assuming (y2 2x+1) is actually (y< 2x+1).
Possible solutions are within the purple section of the attached image.
I hope this is helpful to you.
That job can be handled by +9 and -7 working together.
Answer:
−16(2−−5)
Step-by-step explanation:
hay un factor común entre estos números, por lo que simplemente −16t2+16t+80 divida y reutilice y luego reciba−162+16+80 llegar
−16(2−−5)