Answer:
7/25
Step-by-step explanation:
θ lies in quadrant ii
so 2θ lies in quadrant iv
csc θ=5/3
sin θ=3/5 (sin θ=1/csc θ)
[cos(α+β)=cosαcosβ-sinαsinβ]
cos (2θ)=cos(θ+θ)=cos θ cos θ-sin θ sin θ=cos² θ-sin ²θ=1-sin²θ-sin²θ=1-2sin²θ
=1-2 (3/5)²
=1-2(9/25)
=1-18/25
=(25-18)/25
=7/25
2x² - 15x + 7
(2x - 1)(2x-14)
(2x - 1)(x - 7) x= 1/2 or 7
Range is the outputs possible
w(r(x))=(2-x^2)-2
w(r(x))=2-x^2-2
w(r(x))=-x^2
therefor the range is from 0 to -∞
Let's call the width of our rectangle 
and the length 
. We can say 
, since the length is equal to 4 cm greater than the width.
Also remember that the perimeter of a rectangle is the sum of two times the width and two times the length, or 
. To solve this problem, we can substitute in the information we know, as shown below:
Now, we can substitute in the width we found into the formula for length, which is :
The width of our rectangle is 
cm and the length of our rectangle is 
Answer:
y=x216–6x16+4116
Step-by-step explanation:
plato :)
