1. For x<3, h(x)=x+2
now x+2 is an increasing line (a practical way to check, h(1)=3, h(2)=4)
the largest value it takes is at 3, not inclusive, so h(3)=5 not inclusive.
Range_1= (-∞, 5)
2. for x> or equal to 3, h(x)=-x+8, which is a decreasing line (check h(4)=4, h(5)=3 )
so this line takes its maximal value at x=3, f(3)=5 and then takes any other value to -∞.
Range_2=(-∞,5]
3. Range(h)=Range1∪Range2=(-∞, 5)∪(-∞,5]=(-∞,5] (B)
If you are reflecting across the line y = x, then the x value becomes the y-vale and the y-value becomes the x-value. So the answer would be (6, -1) (Just trade places with x and y.)
Factor f(t) and you can identify the values of t for which the height is zero.
.. f(t) = -16t(t -3)
The projectile lands after 3 seconds in the air. (selection A)
Answer:
in the pics
Step-by-step explanation:
In case you are wondering, I used the pythagorean theorem. If you want to learn how to use it I suggest you google it, there are plenty of sites that explain how to use it.
If you have any questions about the way I solved it, don't hesitate to ask me in the comments below :)
Answer:
No, it is a reflection and a translation
Step-by-step explanation:
It reflects off of A and translates to the right over B