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3 years ago

L need hlp1111111111111111111111111111111111111111111111111111111111

Mathematics

1 answer:

bixtya [17]3 years ago

4 0

Answer:

1:2

Step-by-step explanation:

dude this is easier than answering a question asking about my day :)

You might be interested in

What number is 18.5% of 80?

adoni [48]

Answer:

14.8

Step-by-step explanation:

If you are allowed a calculator, the formula to find the percentage is found by multiplying the percentage by the whole number. For example, when you put in the calculator, 18.5% x 80= 14.8

14.8 being your answer. I hoped this helped!

8 0

3 years ago

Consider the differential equation y'' − y' − 20y = 0. Verify that the functions e−4x and e5x form a fundamental set of solution

KIM [24]

Answer:

Therefore $e^{-4x}$ and $e^{5x}$ are fundamental solution of the given differential equation.

Therefore $e^{-4x}$ and $e^{5x}$ are linearly independent, since $W(e^{-4x},e^{5x})=9e^x\neq 0$

The general solution of the differential equation is

$y=c_1e^{-4x}+c_2e^{5x}$

Step-by-step explanation:

Given differential equation is

y''-y'-20y =0

Here P(x)= -1, Q(x)= -20 and R(x)=0

Let trial solution be $y=e^{mx}$

Then, $y'=me^{mx}$ and $y''=m^2e^{mx}$

$\therefore m^2e^{mx}-m e^{mx}-20e^{mx}=0$

$\Rightarrow m^2-m-20=0$

$\Rightarrow m^2-5m+4m-20=0$

$\Rightarrow m(m-5)+4(m-5)=0$

$\Rightarrow (m-5)(m+4)=0$

$\Rightarrow m=-4,5$

Therefore the complementary function is = $c_1e^{-4x}+c_2e^{5x}$

Therefore $e^{-4x}$ and $e^{5x}$ are fundamental solution of the given differential equation.

If $y_1$ and $y_2$ are the fundamental solution of differential equation, then

$W(y_1,y_2)=\left|\begin{array}{cc}y_1&y_2\\y'_1&y'_2\end{array}\right|\neq 0$

Then $y_1$ and $y_2$ are linearly independent.

$W(e^{-4x},e^{5x})=\left|\begin{array}{cc}e^{-4x}&e^{5x}\\-4e^{-4x}&5e^{5x}\end{array}\right|$

$=e^{-4x}.5e^{5x}-e^{5x}.(-4e^{-4x})$

$=5e^x+4e^x$

$=9e^x\neq 0$

Therefore $e^{-4x}$ and $e^{5x}$ are linearly independent, since $W(e^{-4x},e^{5x})=9e^x\neq 0$

Let the the particular solution of the differential equation is

$y_p=v_1e^{-4x}+v_2e^{5x}$

$\therefore v_1=\int \frac{-y_2R(x)}{W(y_1,y_2)} dx$

and

$\therefore v_2=\int \frac{y_1R(x)}{W(y_1,y_2)} dx$

Here $y_1= e^{-4x}$ , $y_2=e^{5x}$ , $W(e^{-4x},e^{5x})=9e^x$ ,and $R(x)=0$

$\therefore v_1=\int \frac{-e^{5x}.0}{9e^x}dx$

and

$\therefore v_2=\int \frac{e^{5x}.0}{9e^x}dx$

The the P.I = 0

The general solution of the differential equation is

$y=c_1e^{-4x}+c_2e^{5x}$

7 0

3 years ago

All multiplication facts that us have a product of 32

Iteru [2.4K]

2x16
4x8
And of course 1x32

6 0

4 years ago

Read 2 more answers

Please please helppp

Leya [2.2K]

Answer:

This isn't really that hard to solve.

Step-by-step explanation:

For the first one (H): 3 units to the left of 0.

This has to mean that our integer will be negative, and thus, -3 should be written. To the right of 0 would mean it's positive. So, you would find the spot for -3 on the number line and write the letter "H."

The last one (H): not positive or negative.

This means that the integer would have to be 0, as it satisfies the condition that the integer is neither positive (+) nor negative (-). So, you would find the spot marked 0 on the number line and write the letter "H."

If you have any more questions, I would be happy to help, but, personally, this seems like a straightforward assignment.

6 0

3 years ago

Mrs.krabappel is buying composition books for her classroom. Each composition book cost 1.25.

Aleksandr-060686 [28]

Answer: S x 1.25 = A

Step-by-step explanation:

Where S is the number of students and A is your final price. If each book cost 1.25, then she will have to pay 1.25 for every kid.

8 0

3 years ago