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zhenek [66]
3 years ago
11

The area of the rectangular flowerbed is 20.4 square meters with a length of 12 square meters. How many meters of edging are nee

ded to go around the flowerbed? Explain.
Mathematics
2 answers:
juin [17]3 years ago
8 0

Answer:

<h2>There are needed 27.4 meters to go around the flowerbed.</h2>

Step-by-step explanation:

In this problem, we have to calculate the perimeter of the flowerbed, which is the sum of all sides of the rectangular figure.

So, we know that the area of the flower bed is: 20.4m^{2}

Its length is: 12m

As a rectangle, its area would be:

A=(length)(width)\\20.4=12w\\w=\frac{20.4}{12}=1.7

Now we know the length, we can find the perimeter, remember that's just the sum of all sides, that is:

P=l+l+w+w=2l+2w=2(l+w)\\P=2(12+1.7)=27.4

Therefore, there are needed 27.4 meters to go around the flowerbed.

posledela3 years ago
4 0
A = lw
20.4 = 12w
1.7 = w

P = 2 (l + w)
P = 2 (12 + 1.7)
P = 2 (13.7)
P = 27.4 m
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2 years ago
I have 345 students and I need to fit them all into chairs. However, there are some requirements my seating plan has to keep to:
sveta [45]

In each row, the 15 number of the student is arranged. For the given condition, the equal number of the student is to be arranged.

<h3>What is seating arrangement?</h3>

A seating arrangement is an arrangement shows that how the peoples are arranged so that the complete utilization is done.

The given data in the problem is;

The total no of student is 345 students

If the same number of the students are to be arranged for the given row, the following calculation is done;

The numbers of the student in each row is found as;

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Hence, in each row, the 15 no of the student is arranged.

To learn more about the seating arrangement, refer to the link;

brainly.com/question/13492666

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3 0
2 years ago
Find the length of diagonal HJ. Round to the nearest hundredth.
Alisiya [41]

Answer:

The length of the diagonal HJ is 10.82 units

Step-by-step explanation:

* Lets revise the rule of the distance between two points

- d=\sqrt{(x_{2}-x_{1})^{2}+(y_{2}-y_{1})^{2}}, where

 (x_{1},y_{1}) and (x_{2},y_{2}) are the two points

* Lets use this rule to find the length of the diagonal HJ

∵ The coordinates of point H are (-4 , 3)

∵ The coordinates of point J are (5 , -3)

∴ x_{1}=-4 and x_{2}=5

∴ y_{1}=3 and y_{2}=-3

- Lets find the length of the diagonal HJ by using the rule above

∴ HJ = \sqrt{(5-(-4))^{2}+(-3-3)^{2}}=\sqrt{(5+4)^{2}+(-6)^{2}}

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7 0
3 years ago
3. Factor.
sleet_krkn [62]
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For #4, we see that the common factor is 10m because 10m * 2n = 20mn and 10m * 3 = 30m so once we take 10m out of the original, it becomes 10m(2n-3)
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3 years ago
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5 0
3 years ago
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