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Verizon [17]
3 years ago
12

F(x)= 1/2 square root of x-3 ... find y intercept ​

Mathematics
1 answer:
Veronika [31]3 years ago
7 0

Answer:

if so 2130.12548...x^2

Step-by-step explanation:

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Simplify the expression: <br>2b – 5b + 7 + 3b
Leona [35]

Answer:

7

Step-by-step explanation:

2b - 5b is -3b so it leaves the equation with -3b + 7 + 3b

-3b + 3b cancells out to 0 so it leaves the final answer to 7

5 0
3 years ago
I am a 2 digit number.
AlexFokin [52]

Answer:

65

Step-by-step explanation:

6+5=11

5 0
4 years ago
While driving to the school, I was 20 miles from the school at 7:00. By 7:15, I was 8 miles away from the school. What was my ra
Contact [7]

Answer:

your rate of change was 40%

Step-by-step explanation:

8 0
3 years ago
Match the verbal description with the part of the graph it describes.
lara31 [8.8K]

Answer:

1F

2C

3A

4E

5D

6B

Step-by-step explanation:

Good luck!

8 0
3 years ago
An object is heated to 100°. It is left to cool in a room that
stepladder [879]

Answer:

Step-by-step explanation:

Use Newton's Law of Cooling for this one.  It involves natural logs and being able to solve equations that require natural logs.  The formula is as follows:

T(t)=T_{1}+(T_{0}-T_{1})e^{kt} where

T(t) is the temp at time t

T₁ is the enviornmental temp

T₀ is the initial temp

k is the cooling constant which is different for everything, and

t is the time (here, it's in minutes)

If we are looking first for the temp after 20 minutes, we have to solve for the k value.  That's what we will do first, given the info that we have:

T(t) = 80

T₁ = 30

T₀ = 100

t = 5

k = ?

Filling in to solve for k:

80=30+(100-30)e^{5k} which simplifies to

50=70e^{5k} Divide both sides by 70 to get

\frac{50}{70}=e^{5k} and take the natural log of both sides:

ln(\frac{5}{7})=ln(e^{5k})

Since you're learning logs, I'm assuming that you know that a natural log and Euler's number, e, "undo" each other (just like taking the square root of something squared).  That gives us:

-.3364722366=5k

Divide both sides by 5 to get that

k = -.0672944473

Now that we have a value for k, we can sub that in to solve for T(20):

T(20)=30+(100-30)e^{-.0672944473(20)} which simplifies to

T(20)=30+70e^{-1.345888946}

On your calculator, raise e to that power and multiply that number by 70:

T(20)= 30 + 70(.260308205) and

T(20) = 30 + 18.22157435 so

T(20) = 48.2°

Now we can use that k value to find out when (time) the temp of the object cools to 35°:

T(t) = 35

T₁ = 30

T₀ = 100

k = -.0672944473

t = ?

35=30+100-30)e^{-.0672944473t} which simplifies to

5=70e^{-.0672944473t}

Now divide both sides by 70 and take the natural log of both sides:

ln(\frac{5}{70})=ln(e^{-.0672944473t}) which simplifies to

-2.63905733 = -.0672944473t

Divide to get

t = 39.2 minutes

3 0
4 years ago
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