$(\stackrel{x_1}{2}~,~\stackrel{y_1}{4})\hspace{10em} \stackrel{slope}{m} ~=~ -3 \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{4}=\stackrel{m}{-3}(x-\stackrel{x_1}{2}) \\\\\\ y-4=-3x+6\implies y=-3x+10$

7 0

1 year ago

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How do you identify if the equation is linear, exponential, or quadratic?

Naddika [18.5K]

Answer:

It's form. Linear is a normal line, exponential is a curvy line, and quadratic is a u shape with the vertice on the y-axis line, making half of the u on the left quadrant and the other half on the right quadrant

Step-by-step explanation:

first is linear, second is exponential and third is quadratic

8 0

3 years ago

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A soup recipe calls for 2 3/4 quarts of vegetable broth.An open can of broth contains 1/2 quart of broth.How much more do you ne

Annette [7]

1/2 - 2/4

2 3/4 - 2/4 + 2 1/4 still needed

5 0

3 years ago

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Solve for x. <br><br> 12x/5 = 18

jarptica [38.1K]

For this problem you have to isolate the variable. To do this you must inverse the operations. Multiply 18 by 5, then divide by 12 to get your answer of 7.5

3 0

3 years ago