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Bezzdna [24]
3 years ago
8

Answer as much as possible

Mathematics
1 answer:
VLD [36.1K]3 years ago
5 0
20. 3n + 2
21. 0.5n - 9
22. n - 9^2
23. |-16| + n
24. |-8 - 2n|
25. n(9 + 3)
26. n(22 - 5)
27. n(4 - 3)
28. 7(n + 3)
29. (-19 + n)/10
30. (2 + n)/4
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What is the value of x
Colt1911 [192]

Answer:

The value of x are all real number on x-axis the number that falls under x

example of the value of x are in this equation

y=2+5x

2x+6y=60

to find x

let make the first one equation 1 and the second equation 2

now, put equation 1 in equation 2

2x+6(2+5x)=92

open the by multiplying every thing in the bracket by 6

2x+12+30x=92

combine the like terms

2x+30x=69212

32x=80

now divide via by 32

32x/32=80/32

x=5/2

7 0
3 years ago
PLEASE HURRY WILL MARK ANSWER AS BRAINLIEST!!!
WITCHER [35]

Answer:

112

Step-by-step explanation:

5 0
3 years ago
Find the absolute minimum and absolute maximum values of f on the given interval. f(t) = 3 (*sqaure root sign*) t (20 − t), [0,
mafiozo [28]

9514 1404 393

Answer:

  • maximum: 15∛5 ≈ 25.6496392002
  • minimum: 0

Step-by-step explanation:

The minimum will be found at the ends of the interval, where f(t) = 0.

The maximum is found in the middle of the interval, where f'(t) = 0.

  f(t)=\sqrt[3]{t}(20-t)\\\\f'(t)=\dfrac{20-t}{3\sqrt[3]{t^2}}-\sqrt[3]{t}=\sqrt[3]{t}\left(\dfrac{4(5-t)}{3t}\right)

This derivative is zero when the numerator is zero, at t=5. The function is a maximum at that point. The value there is ...

  f(5) = (∛5)(20-5) = 15∛5

The absolute maximum on the interval is 15∛5 at t=5.

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2 years ago
PLEASEE HELP ME WITH THIS QUESTION!! Ty
kotykmax [81]

Answer:

Give me a heart and 5 stars

Step-by-step explanation:

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2 years ago
Please Help. Thank you
jeyben [28]
The answer is D. A translation does not change a figure's size or shape because each of its points are moved the same amount and in the same direction(s).
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