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egoroff_w [7]
3 years ago
10

a restaurant holds an anniversary celebration of 90 diners. Only 27 are offered free dessert, what is the percent of dinners not

offered free dessert?
Mathematics
1 answer:
alex41 [277]3 years ago
6 0

Answer:

70%

Step-by-step explanation:

(90-27)/90

=63/90

=0.7

Changing it to percentage:

=70%

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I need help with this question and it’s very urgent!!!!
andreev551 [17]

Answer:

AAS

Step-by-step explanation:

8 0
3 years ago
A box of fruit has three times as many nectarines as grapefruit. Together there are 64 pieces of fruit. Write the equation that
Basile [38]

Answer:

4g = 64

Step-by-step explanation:

Let n = the number of nectarines

and g = the number of grapefruit

We have two conditions that must be satisfied to represent the situation:

(1)         n = 3g

(2) n + g = 64

If you need one equation, we can substitute (1) into (2) and get

4g = 64

7 0
3 years ago
Which expression is equivalent to StartRoot 128 x Superscript 8 Baseline y cubed z Superscript 9 Baseline EndRoot? Assume y grea
Nataly [62]

Answer:

Option C.

Step-by-step explanation:

The given expression is  

\sqrt{128x^8y^3z^9}

It can be written as

\sqrt{(64\cdot 2)\cdot x^8\cdot y^{2+1}\cdot z^{8+1}}

=\sqrt{8^2\cdot 2\cdot (x^4)^2\cdot y^{2}\cdot y\cdot (z^{4})^2\cdot z}

=\sqrt{(8x^4yz^4)^2\cdot 2yz}

=8x^4yz^4\sqrt{2yz}

Therefore, the correct option is C.

6 0
3 years ago
If P divided by 10 is 2. What is the value of P ?
barxatty [35]

Answer:

The value of P is 20 .

Step-by-step explanation:

Firstly, you have to create an expression in terms of p using the information :

\frac{p}{10}  = 2

Next, you have to multiply both sides by 10 :

\frac{p}{10}  \times 10 = 2 \times 10

p = 20

8 0
3 years ago
Read 2 more answers
Solve tan 10 - tan 50 +tan 70 with trigonometry.
Jobisdone [24]
Below is the solution, I hope it helps.

  <span>i) tan(70) - tan(50) = tan(60 + 10) - tan(60 - 10) 

= {tan(60) + tan(10)}/{1 - tan(60)*tan(10)} - {tan(60) - tan(10)}/{1 + tan(10)*tan(60)} 

ii) Taking LCM & simplifying with applying tan(60) = √3, the above simplifies to: 

= 8*tan(10)/{1 - 3*tan²(10)} 

iii) So tan(70) - tan(50) + tan(10) = 8*tan(10)/{1 - 3*tan²(10)} + tan(10) 

= [8*tan(10) + tan(10) - 3*tan³(10)]/{1 - 3*tan²(10)} 

= [9*tan(10) - 3*tan³(10)]/{1 - 3*tan²(10)} 

= 3 [3*tan(10) - tan³(10)]/{1 - 3*tan²(10)} 

= 3*tan(30) = 3*(1/√3) = √3 [Proved] 

[Since tan(3A) = {3*tan(A) - tan³(A)}/{1 - 3*tan²(A)}, 
{3*tan(10) - tan³(10)}/{1 - 3*tan²(10)} = tan(3*10) = tan(30)]</span>
7 0
3 years ago
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