Shawndra is correct
She made two statements, and both are true:
1. It is not possible to draw a trapezoid that is a
rectangle.
This is true because a trapezoid<span> is a quadrilateral that has exactly one pair of
parallel sides, whereas a rectangle is a parallelogram (i.e. it has two
pairs of parallel sides)</span>
2. It is possible to draw a square that is a rectangle.
This is true because a rectangle refers to any parallelogram
with right angles. A square is also a parallelogram (has two pairs of opposite
sides) with right angles. In fact, all squares are rectangles; only that they
are a special kind of rectangle, where all the sides are equal in length.
For the fourth term r = 3
Fourth term = 6C3(x)^(6 - 3) (4y)^3 = 20x^3 (64y^3) = 1,280x^3y^3
Answer:
-x+20=31
Step 1: Subtract 20 from both sides.
−x+20−20=31−20
−x=11
Step 2: Divide both sides by -1.
−x
−1
=
11
−1
x=−11
Answer:
x=−11
Part A: 9 and 7+2x
Part B: 1 term
Part C: 2 from 2x
ythe base of the triangle is 15 + 8 = 23 feet
and the angle is 50 degrees
to find the height of the street lamp
multiply the base ( 23) by the Tan(50)
tan(50) x 23 = 27.41 feet rounded to nearest foot would be 27 feet
